How High Can We Count - Game

[Duki]

Ok,

Just thought this would be neat... here are the rules... very simple.

* Numbers must follow logical order
* You can not post two consecutive posts
* Have fun! :mrgreen:

I'll start:

1

[~s.o.s~]

Or should I say "how high our post count can go ? "... ;)

2

[Duki]

ah, was it that obvious? :p jk

3

[~s.o.s~]

ah, was it that obvious?

Being long enough with the site has its own merits... ;)

Btw, why not modify the game to add a litte twist to it by deriving the next number using some mathematical functions.. ? Something like:

3 * 3 => 9

[Duki]

That sounds like a great plan....

so instead of 4 we would type something to the effect of:

16/4 -=> 4 ?

or is that not what you meant

[~s.o.s~]

so instead of 4 we would type something to the effect of:

16/4 -=> 4 ?

or is that not what you meant

No, it doesn't necessarily have to be in sequential order. Put up any kind of mathematical operation along with the previous number to come up with a result.

Eg.

4 * sin (PI / 6) => 2

[Duki]

ah ok, sounds neat... should truncating be required?

2(sqrt(9)) => 6

[~s.o.s~]

6 + 1 => 7

[Duki]

7pow(2,2) -=> 28

[Dani]

28 / 7 = 4

Anyone know how to use the [tex] bbcode? I don't know latex :(

[Duki]

4-4=0

[jimlaver]

[(Cos 0)(Sin 90)] = 1

[~s.o.s~]

1 * cos (PI / 3) => 0.5

[Duki]

if f(x) = f(.5)

f(x) = x * (21/2) =

x = 5.25

[~s.o.s~]

5.25 + 94.75 => 100

[linux]

100(PI) = 314.159...... (can I stop?)

[Duki]

324.159 - 323.159 = 1

[~s.o.s~]

sqrt (1) => 1

[jwenting]

tan(1) = 1.5574077246549022305069748074584

[Duki]

(cos)1.5574077246549022305069748074584 = ~1

[~s.o.s~]

factorial (1) => 1

[Duki]

1 = 1

[christina>you]

|4x - 20(1)| = 60

x = 20

algebra II =/

[Duki]

20 - .001 = 19.999

[christina>you]

19.999 * 1000 = 19999

:)

[Duki]

1999 - 2000 = -1

[christina>you]

-1 - (-395) = 394

skills baby.

[Duki]

394 -(-(-(-(-(-(-393)))))) = 1

[christina>you]

|-1| = 1

1 = 1

;)

[Duki]

int x = 12
int y

if (x > 12)

y = 89 * 42;

else

y = 1;