I thought it was funny, but I don't know why it got edited.
server_crash
64
Postaholic
nightowl512
0
Newbie Poster
Old Fashon Vic 20 BASIC
10 fort = 1 to 10
20 print t
30 next t
julesjacobs
0
Newbie Poster
puts (1..10).to_a
pty
882
Posting Pro
in Delphi :
program simplecount;
var
i: Integer;
begin
for i := 1 to 10 do
WriteLn(IntToStr(i));
end.and in perl (because everyone loves perl) :
#!/usr/bin/perl
for($i = 0; $i < 10; ++$i)
{
print $i . "\n"
}I use Ruby mostly these days. From previous posts you can tell why; so so elegant
Rashakil Fol
978
Super Senior Demiposter
Team Colleague
Here's another Haskell version.
main = mapM_ (putStrLn . show) [1..10]
Puckdropper
7
Posting Pro in Training
HTML
<html>
<head><title>It's an instructional language</title></head>
<body>
1,
2,
3,
4,
5,
6,
7,
8,
9,
10
</body>
</html>If we apply some simple definitions to terms, HTML is a valid language to use for this. (i.e. Program: Series of instructions to be executed. HTML thusly instructs the interpreter to write the code.)
Ada
with Ada.Integer_Text_IO;
procedure print10 is
begin
for i in integer range 1..10 loop
Ada.Integer_Text_IO.put(i);
end loop;
end print10;Yet another C++ version:
#include <iostream>
using namespace std;
int main()
{
int i=1;
cout << i; // 1
cout << ++i; // 2
cout << ++i; // 3
cout << ++i; // 4
cout << ++i; // 5
cout << ++i; // 6
cout << ++i; // 7
cout << ++i; // 8
cout << ++i; // 9
cout << ++i; // 20
}
WaltP
2,905
Posting Sage w/ dash of thyme
Team Colleague
ForTran
integer i
do 100 i=1,10
100 write(5,200) i
200 format("i3")
end
WaltP
2,905
Posting Sage w/ dash of thyme
Team Colleague
8080 Assembler
code segment ; Start of the code
assume cs:code ; Load code segment register
org 100h ; and set program up as a .COM file
start:
assume cs:code
mov ax, 1 ; Start at 1
loop:
call outdec ; Output the AX register
inc ax ; next value
cmp ax, 10 ; Above 10 yet?
jle loop
mov al, 0
mov ah, 4Ch
int 21h ; Exit
; ******************************** ;
outdec:
push ax ; save AX
mov bx, 10 ; divisor
mov cx, 3 ; # characters
convloopd:
mov dx, 0 ; zero high word for div
div bx ; divide by 10
add dl, 30h ; convert remainder to char
push dx ; Save character
loop convloopd ; do it til cx = 0
mov cx, 3 ; start another loop
outloopd:
pop dx ; get the character
mov ah, 02h ; output character fcn
int 21h ; output it
loop outloopd
mov ah, 02h
mov dl, ' '
int 21h ; output 2 spaces
int 21h
pop ax ; restore original number
ret
code ends
end start
Rashakil Fol
978
Super Senior Demiposter
Team Colleague
Brainfuck:
+++[>++++[>++++<-]<-]>
++++++++++>
+.<.>+.<.>+.<.>+.<.>+.<.>
+.<.>+.<.>+.<.>+.<.>
--------.-.<.
Rashakil Fol
978
Super Senior Demiposter
Team Colleague
Haskell, with the integer datatype implemented from scratch:
First, let's implement a datatype for storing integers.
> data IntType = Zero
> | Succ IntType
> | Pred IntType
> deriving Eq
Then we'll want to implement comparison for integers.
> instance Ord IntType where
> compare (Pred xt) (Pred yt) = compare xt yt
> compare (Pred _) _ = LT
> compare _ (Pred _) = GT
> compare Zero Zero = EQ
> compare (Succ xt) (Succ yt) = compare xt yt
> compare (Succ _) _ = GT
> compare _ (Succ _) = LT
Integers should be enumerable too...
> instance Enum IntType where
> toEnum 0 = Zero
> toEnum n = accume n Zero
> where accume 0 k = k
> accume n k
> | n < 0 = accume (n+1) (Pred k)
> | n > 0 = accume (n-1) (Succ k)
> fromEnum k = adder 0 k
> where adder n Zero = n
> adder n (Pred kt) = adder (n-1) kt
> adder n (Succ kt) = adder (n+1) kt
> succ (Pred kt) = kt
> succ k = Succ k
> pred (Succ kt) = kt
> pred k = Pred k
> enumFrom x = iterate succ x
> enumFromTo x y
> | x == y = [x]
> | otherwise = x : enumFromTo (succ x) y
And we need to perform arithmetic.
> instance Num IntType where
> x + Zero = x
> Zero + y = y
> (Pred xt) + y = xt + pred y
> (Succ xt) + y = xt + succ y
> x - Zero = x
> x - (Pred yt) = succ x - yt
> x - (Succ yt) = pred x - yt
> Zero * y = Zero
> (Pred xt) * y = xt * y - y
> (Succ xt) * y = xt * y + y
> abs x@(Pred _) = Zero - x
> abs x = x
> signum (Pred _) = Pred Zero
> signum (Succ _) = Succ Zero
> signum Zero = Zero
> fromInteger n = accume n Zero
> where accume 0 k = k
> accume n k
> | n < 0 = accume (n+1) (Pred k)
> | n > 0 = accume (n-1) (Succ k)
They must be an instance of Real in order to be an instance of
Integral.
> instance Real IntType where
> toRational = toRational . toInteger
Our integers are indeed integral :-)
> instance Integral IntType where
> quotRem Zero _ = (Zero, Zero)
> quotRem n d = appsig (signum n * signum d) (foo n d)
> where appsig k (q,r) = (k*q, k*r)
> foo n d = countup (abs n) (abs d) Zero
> countup n@(Pred _) d c
> = (pred c, n + d)
> countup n d c
> = countup (n - d) d (succ c)
> toInteger k = acc 0 k
> where acc n Zero = n
> acc n (Pred kt) = acc (n-1) kt
> acc n (Succ kt) = acc (n+1) kt
Finally, implement an instance of the Show class, for converting
integers to strings.
> instance Show IntType where
> show n | n == Zero = "0"
> | n < Zero = '-' : show (negate n)
> | n > Zero = onshow n ""
> where ten = Succ $ Succ $ Succ $ Succ $ Succ five
> five = Succ $ Succ $ Succ $ Succ $ Succ Zero
> onshow Zero s = s
> onshow k s = let (q,r) = quotRem k ten
> in onshow q (charate r : s)
> charate Zero = '0'
> charate (Succ kt) = succ (charate kt)
Might as well show off that it works...
> greaterroot :: IntType -> IntType
> greaterroot n = head [k | k <- [Zero ..], k * k >= n]
Finally, our main function! Make a list of perfect squares from Zero
to (Succ (Succ (Succ ... (one hundred times) ... (Succ Zero) ... ))),
then find their square roots, and output them!
> main :: IO ()
> main =
> mapM_ (putStrLn . show) $ map greaterroot squares
> where squares = map (\x -> x*x) [one .. ten]
> one = Succ Zero
> two = one + one
> five = two + two + one
> ten = two * five
Jessehk
20
Newbie Poster
I just started teaching myself O'Caml :)
let rec range s f =
if s > f then []
else s :: range (s + 1) f ;;
let count s f =
List.iter (fun i -> Printf.printf "%d " i) (range s f) ;;
count 1 10 ;;
MattEvans
473
Veteran Poster
Team Colleague
Featured Poster
XML/XSLT
I guess XML isn't a language, and XSLT doesn't have to be, but this is certainly programmatic. It requires an input XML file and produces an HTML output file with the numbers one to ten separated by line breaks. The elements in the XML input file are irrelevant, as long as the root element is called "lots", and every "lots" element contains one more "lots" element than its parent. Until you get to ten of course.
Here's the input file (lots.xml)
<?xml version="1.0" encoding="UTF-8"?>
<?xml-stylesheet type="text/xsl" href="countem.xsl"?>
<lots>
<lots><lots><lots>
<lots><lots><lots>
<lots><lots><lots>
<right /><what /><we /><are /><going /><to />
<do /><here /><is /><create /></lots><of />
<elements /><infact /><they /><are /><xml />
<elements /><and /></lots><of /><them /><are />
<in /><this /><file /><yes /></lots><of /><em />
<doesnt /><matter /><whats /><in /></lots><of />
<them /><because /><most /><infact /></lots><of />
<them /><are /><just /></lots><and /><thats />
<got /></lots><of /><importance /></lots><and />
</lots>
</lots>And heres the XSLT stylesheet:
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet xmlns:xsl="[URL]http://www.w3.org/1999/XSL/Transform[/URL]" version="1.0">
<xsl:template match="/">
<html>
<head><title>Count to ten!</title></head>
<body>
<xsl:apply-templates select="lots"/>
</body>
</html>
</xsl:template>
<xsl:template match="lots">
<xsl:value-of select="count(*)"/>
<br />
<xsl:apply-templates select="lots"/>
</xsl:template>
</xsl:stylesheet>Matt
MattEvans
473
Veteran Poster
Team Colleague
Featured Poster
By programming myBrain (in real-time) to use the "handwriting" library : system requirements included "pencil" and "paper" : tested in the "my kitchen" environment only.
Yep that's right, I wrote down the numbers 1 to 10 on a piece of paper. It had a very short implementation time, and I even drew a squiggly line around the numbers when I'd finished.
I unfortunately can't provide any evidence to support this feat - you'll just have to trust me.
Matt
andor
25
Posting Whiz in Training
MIPS assembler. Using SPIM simulator
.data
str1: .asciiz "1 2 3 4 5 6 7 8 9 10"
.globl main
.text
main:
la $a0, str1 # load string address into $a0 and I/O code into $v0
li $v0, 4
syscall # execute the syscall to perform input/output
# via the console
li $v0, 10 # syscall code 10 for terminating the program
syscall
Bench
212
Posting Pro
Just been playing about with C++ Templates, and thought of this thread :)
(By the way, only 44 posts?! we can do better than that...! )
#include <iostream>
template<int i> void count()
{
std::cout << i << std::endl;
count<i+1>();
}
template<> void count<10>()
{
std::cout << 10 << std::endl;
}
int main()
{
count<1>();
}
Jessehk
20
Newbie Poster
(By the way, only 44 posts?! we can do better than that...! )
That we can. On the forum where I stole this idea, we got to 500. :)
#include <iostream>
template <int n>
class Counter {
public:
Counter() {
Counter<n - 1> count;
std::cout << n << std::endl;
}
};
template <>
class Counter<0> {
public:
Counter() {}
};
int main() {
Counter<10> count;
}EDIT: I'm in shock! I'm sorry that my code is so similar to yours. It was a complete coincidence. :eek:
Bench
212
Posting Pro
EDIT: I'm in shock! I'm sorry that my code is so similar to yours. It was a complete coincidence. :eek:
heh, I think you can claim that yours is a more OO version :)
srinivasdama
2
Newbie Poster
#include<stdio.h>
void main(){
static
andor
25
Posting Whiz in Training
#include<stdio.h>
void main(){
static
I think you should edit this
srinivasdama
2
Newbie Poster
#include<stdio.h>
void main(){
static int i =0;
while(++i<=10){
printf("%d\n",i);
main();
}
andor
commented:
but the idea is nice (andor)
+2
andor
25
Posting Whiz in Training
#include<stdio.h>
void main(){
static int i =0;
while(++i<=10){
printf("%d\n",i);
main();
}
Don't use void main() instead use int main() . Never call main recursivly. Ok i can be static but why it's not just auto variable. For last you need one more } . After all forums are to improve our skills.
Bye
andor
25
Posting Whiz in Training
#include <stdio.h>
int main()
{
char c[] = {4, 16, 2, 0, 68, 65, 77, 83, 21, 84, 89, 0, 71, 82, 81, 78, 77, 0, 106, 1, '\n'};
char * p = c;
char * tmp = "500 ways to print [1..10]!";
while(*p != '\n')
putchar(*p++^*tmp++);
return 0;
}
TylerSBreton
13
Junior Poster in Training
Another C#:
public class Count{
public static void main(){
int [] a = {1,2,3,4,5,6,7,8,9,10};
foreach(int i in a)
System.Console.Write(i + " ");
}
}
pty
882
Posting Pro
what is the shortest way of printing 1..10 in any language?
i can't see any being much shorter than this :
1.upto(10) { |i| puts i }
Rashakil Fol
978
Super Senior Demiposter
Team Colleague
Here's another Haskell one:
main = mapM_ print [1..10]
MattEvans
473
Veteran Poster
Team Colleague
Featured Poster
what is the shortest way of printing 1..10 in any language?
i can't see any being much shorter than this :
1.upto(10) { |i| puts i }
In perl:
print 1..10;
or even shorter:
die 1..10;
Rashakil Fol
978
Super Senior Demiposter
Team Colleague
Well, technically, that prints 12345678910.
Here's a Perl 6 version:
say for 1..10
Mushy-pea
36
What, you can change this tag?
In Sinclair Spectrum 64 K BASIC:
for n = 1 to 10
print n
next n
Mouche
python:
print "1, 2, 3, 4, 5, 6, 7, 8, 9, 10"
Mouche
python:
for x in range(1,11):
print x,
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