I am writing a program in which i will be using 2 functions, one for writing integers into a text file & second for reading them back in integer form. while i did not faced in writing int say 100 numbers into a text file. i am stuck on reading from it. my program requirement is that, i want to read only one integer at a time when i call read function & when i call read function next time, it should return next number from the file. i think their can be 2 ways to solve this problem. first is that once i have read a number from the file, that number should be deleted & when i call read function next time, it will return next number from the file. in second method i can use pointer to keep track of them. i am not sure how to do it. please help.
sksingh73
0
Newbie Poster
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kbshibukumar
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Junior Poster in Training
Try to post the code you developed.
sksingh73
0
Newbie Poster
code is ..........
int writefile(char *str, int size)
{
uint32_t c;
ofstream outfile;
outfile.open("output.txt");
for(int i=0;i<size;i++)
{
c = hashlittle(str, strlen(str), 0);
printf("%.8x\n", c);
outfile<<c<<endl;
sprintf(str, "%u", c);
}
outfile.close();
return 1;
}
uint32_t fetchfile(int ctr)
{
uint32_t hash, array[10];;
ifstream myfile ("output.txt");
myfile.is_open();
for(int i=0;i<10;i++)
{
myfile>>array[i];
printf("value fetched from file: %.8x\n", array[i]);
}
hash = array[ctr];
printf("Current value fetched from file: %.8x\n", hash);
myfile.close();
return hash;
}
int main()
{
//uint32_t c;
//int ctr =0;
char str[80];
cout<<"enter string: ";
cin.get(str,80);
cout<<endl;
writefile(str,10);
fetchfile(0);
return 0;
/*
ofstream outfile;
outfile.open("output.txt");
for(int i=0;i<10;i++)
{
c = hashlittle(str, strlen(str), 0);
printf("%.8x\n", c);
outfile<<c<<endl;
sprintf(str, "%u", c);
}
uint32_t hash, array[10];;
ifstream myfile ("output.txt");
myfile.is_open();
for(int i=0;i<10;i++)
{
myfile>>array[i];
printf("value fetched from file: %.8x\n", array[i]);
}
hash = array[ctr];
printf("value fetched from file: %.8x\n", hash);
myfile.close();
*/
}
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