How do I round off

For the first case:
If your salary is 1000.23 it has to be 1000.25:
We multiply 1000.23 by 20, round it off to the nearest integer and divide it back by 20 :) ...

Edit:: In the second case (if your salary is 1000.26 and it has to rounded off to 1000.30): the Math.round function should work fine here !

Hope this helps !

If you want 1000.26 to round to 1000.30, you would have to use Math.ceil.

I hope this snippet does what you want :

using System;

namespace ConsoleApplication1
{
    class Program
    {
        static void Main(string[] args)
        {
            double d1 = 1000.23;
            double d2 = 1000.26;
           
            Console.WriteLine("d1= {0:F}", roundNum(d1,2));
            Console.WriteLine("d2= {0:F}", roundNum(d2,2));
            
            Console.ReadKey();
        }
     
        public static double roundNum(double num, int place)
        {
            double d = num * Math.Pow(10, place - 1);
            double floorValue = Math.Floor(d);
            if ((d - floorValue) > .5)
            {
                return (floorValue + 1) / Math.Pow(10, place - 1);
            }
            else
            {
                return (floorValue + 0.5) / Math.Pow(10, place - 1);
            }
        } 
    }
}

This does not work if place is smaller than 1, you have to test for it!

Hi !!!
I want to make window application In which I want to roundoff two numbers to nearest tens or hundreds or thousands....
After rounding off,then I want to find its sum \diff\mult\div...
On the form I have three textboxes i.e.one for entering the question,second for nearest roundoff(10,100,100) and another textbox for displaying final result.
For example-:
In first text box I enter 367*231
In the second I enter 100
Now in third textbox result should be 80000(i.e 400*200=80000 because nearest 100 of 367 is 400 and that of 231 is 200)

can anyone give me C# code for making this application...

This is code to round 231 to the nearest hundred :

int i = 231;
double d = i/100.0;
double r = Math.Round(d, 0);
 int roundInt = (int)r * 100;

Thanks for the code.......
this I already knew......
problem is that how will the computer recognise the expression in textbox1 i.e 367*231 and evaluate to solve the value

If you want to get help, post this question again in a new thread because this is a whole other issue then just rounding off.:-O
We will see you there:)