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<?php $mysql_host = "***"; $mysql_database = "***"; $mysql_user = "***"; $mysql_password = "***"; mysql_connect($mysql_host,$mysql_user,$mysql_password); mysql_select_db($mysql_database); $query = "SELECT * FROM people coming"; $result = mysql_query($query); while($w=mysql_fetch_array($result)) { echo $w['Name']; } ?> this doesnt work--Warning: mysql_fetch_array(): supplied argument is not a valid MySQL result resource y? 
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