Well, it's printing "not a palindrome" for all the numbers i punch
Including many palindromes..

/* the thing is that i need to check if a given number (n) is a palindrome. i also used limits.h to identify if the number is

is exceeding the limit. i came up with this beut it's no good. any ideas? */

#include <iostream>

#include <stdlib.h>

#include <limits.h>

#include <math.h>

using namespace std ;

int main ()

{

int a, n, m=0, t ;

cout<<"Enter query number:"<<endl ;

cin>>n ;

t=n ;

  while (n)

    {

      {

       a=n%10 ;

       n=n/10 ;

       m=m*10+a ;

        {

         if (INT_MAX-n<a)

         cout<<"overload" ;

        }

      }

if (t==m)

  cout<<t<<"this number is already a palindrome"<<endl ;

else

  cout<<t<<"this number is not a palindrome"<<endl ;

    }

return 0 ;

}
//A1  = 1
//An = An-1 +sqrt(An-1)     for n > 1.

//i need to find An of the series according to the estimation An=(n^2)/4

//how do i write a member of the series, let's say "An" in the code and to apply "n>1" in the code?