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i want to show my graph values but its show null output. i show you in image output also // JavaScript Document $(document).ready(function(){ $.ajax({ url: "data.php", method: "GET", success: function(data) { console.log(data); var playerid = []; var score = []; for(var i in data) { playerid.push("Player " + data[i].playerid); score.push(data[i].score); … 
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hi i used this simple form which are these..but i want to protect password from oracle database if user enter wrong name and password then not login otherwise login <!DOCTYPE HTML> <html> <head><br> <style> .error {color: #FF0000;} </style> </head> <body style="font-family: verdana, sans-serif;";> <hr /> <div style="width: 77%; height: 300px; … 
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i have a two menu bar option which are home and my account after login my user and pswd its show home page but when i change home to my account page its show message below and logout Notice: Undefined index: user in folder\myaccount.php Notice: Undefined index: pswd in folder\myaccount.php …
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hi everyone hope you are all well... i am login with userid and password and i want to display there username after login from my oracle database how?
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i want to display my image from a folder but its not work what i change in code to work <?php $dir_path = "/xampp/htdocs/image/"; $extensions_array = array('jpg','png','jpeg'); if(is_dir($dir_path)) { $files = scandir($dir_path); for($i = 0; $i < count($files); $i++) { if($files[$i] !='.' && $files[$i] !='..') { // get file name … 
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hi everyone i need help in my query while user login. <?php $username = $_POST["username"]; $password = $_POST["password"]; $con = oci_connect("user","pswrd","db"); if(! $con) { die('Connection Failed'.oci_error()); } $query = "SELECT username, password FROM users WHERE username=$username"; $stmt = oci_parse($conn, $query); $row = oci_fetch_array($stmt, OCI_NUM);; if($row["username"]==$username && $row["password"]==$password) echo"You are a …
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hi everyone hope you all are in good. i have query while login form in php with oracle database..... i want to simple login with database html code: <p> <form method="post" action="<?php echo $_SERVER['PHP_SELF']; ?>"> Username:<br /><input type="text" name="username" size="10" /><br /> Password:<br /><input type="password" name="password" size="10" /><br /> <input …
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hi everyone i need help in my query which is that: 1.which country name i selected from my dropdown list 2.when i select any country_name its show more info in new page.php like (this selected name show more information about country_name e.g. its captical, and cities through database in new … 
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( https://i.stack.imgur.com/1LPVk.png ) i mention my link where output show when i press drop-down button then show empty fields but i have values in my sql table link ( https://i.stack.imgur.com/YEopy.png) but it does not execute my values in drop down list..i need help...when i show error it does not dispaly …
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