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mysqli_real_escape_string() expects parameter 1 to be mysqli, null $idbilik = " ' ". mysqli_real_escape_string($idbilik, $samb) . " ' "; $result = mysqli_query($samb,"SELECT * FROM bilik WHERE idbilik=$idbilik"); while($res = mysqli_fetch_array($result)) i did as u say so madam...add the line u gave before $result..but i am getting the error stated above... 
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mysqli_real_escape_string() expects parameter 1 to be mysqli, null $idbilik = " ' ". mysqli_real_escape_string($idbilik, $samb) . " ' "; $result = mysqli_query($samb,"SELECT * FROM bilik WHERE idbilik=$idbilik"); while($res = mysqli_fetch_array($result)) i did as u say so madam...add the line u gave before $result..but i am getting the error stated above...
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