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[code=c] int main() { int a,b,c; a=b=c=1; c = ++a || ++b && ++c; printf("%d %d %d", a,b,c); } [/code] here the expression is considered from left to right. but the confusion of mine is: && has got higher precedence than that of ||. so ++b && ++c should be …
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hi everyone, i am working on Turbo C 3. here the near pointer is of 16 bits and the far pointers are of 32 bits. i want to know how these logical addresses of 16 and 32 bits are converted into physical address of 20 bits. thanks. 
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