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Hi all, I seem to be having a problem. I get the above error when trying my login script. [CODE]<?php $dbhost = "localhost"; $dbname = "userlogin"; $dbuser = "adminuser"; $dbpass = "xxxxxxx"; $dbtable = "users"; mysql_connect ( $dbhost, $dbuser, $dbpass, $dbtable)or die("Could not connect: ".mysql_error()); mysql_select_db($dbname) or die(mysql_error()); session_start(); $username …
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I am trying to keep two menu lists' option in variables but i dont know whether to use "selected" or "select name" to assign value 1st one which brings "Student Numbers" rows from its column in selected class table. [code=php]$query="SELECT StudentNumber,Student_id FROM $CC"; $result = mysql_query ($query); echo "<select name=\"STUDENT\" …
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I have created two table by generating via forms. My question is although second table's foreign key appears on phpmyadmin it doesnt have that same value with the first table's primary key. currently foreign key has all zero values in all of the rows. Table codes: [code=php]$sql2='CREATE TABLE IF NOT …
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