soroushc

Hi:)the problem im facing is that i created a control Textfield.Example :the user types in 75000 in the textfield and after he or she presses enter the List view appears. But i want them to hit a button so after hitting the button the list view appears?plz help

It's my assignment I have done almost I have completed it.But I have problem in getting input from user(the bank name)here is my assignment question. Customer often wait in the bank..!you have to ask the user the entire as many bank names as he desires and time (waiting time the …

Hey men When i wanna run the code below,i get the famouse [I]don't send[/I] message and i use code::blocks 8.02 [CODE]#include <conio.h> #include <iostream> using namespace std; int main(){ int start,end; double a[start-end][2],p[start-end]; cout<<"Enter a number to begin with : "; cin>>start; cout<<"Enter a number to finish with : "; …

how to get a string using array? and how can I get input in this format string|12.3 12.23 | example;with no space between the lines and when user enter 0 it will exit david|12.3 24.2| Peter|12.4 24.2|

I'm new to C++ and I can't seem to find the problem with my code. I have a function that opens an input file. It asks you to input a file and if it can’t open the file it asks you if you want to try again. If you answer …

Hi, all i have the assignment about program which reads in integers from cin until the user enters a non-integer (a character or EOF), then print out the average. Its pretty simple assignment but i am kind of new. So the following is my code and seems like have some …

For some reason my if statement in both my [I]unionFunction[/I] and [I]intersectFunction[/I] is setting the array equal to 1 rather then comparing it. I've tried to figure out whats wrong but nothing seems wrong to me. I appreciate any help. Here is my program so far: [code] #include "stdafx.h" #include …

HELLO EVERYONEE!I Love programingg!It's a great fun!:) I know how to write program's in C++ and I'm learning Visual C # by my ownself!:) would be glad to meet other programmers:)