callister

[code]#include <iostream> #include <cmath> double f1(double); double f2(double,double); using namespace std; int main() { double dx, dy,x=1.0, y=1.0,xnew,ynew,eps=0.0000001,err=1.0,m=1; while ( fabs(err) > eps ) { dx= -f1(x)/(3.0*sin(x)+cos(x)); dy= (f1(x)*sin(x)+f2(x,y)*(cos(x)-3*sin(x)))/3*sin(x)*(cos(y)+cos(x)*cos(y)); xnew= x+dx; ynew= y+dy; m = (xnew*xnew)+(ynew*ynew); err=sqrt(m); } if ( fabs(err) < eps ) cout<< "dx= " <<dx<<endl; cout<< "dy= …

Guys..Can anyone help me to explain what really happened in the while loop and both of the if else loop that makes this coding can find the root using bisection method.Thank you...[code]#include "stdafx.h" #include <iostream> #include <cmath> #include <iomanip> using namespace std; double f( double); int main ( int argc, …

Guys..I'm trying to understand this coding and I can't understand the for loop. Can someone please explain it to me what happened there. Thank you[code]#include <iostream> using namespace std; int main() { long long int number; cout << "Enter number to test: "; cin >> number; for(int x=2; x<(number/2); x++) …

Hey everybody.. I have some problem here. This is the question: Find a root of the equation on the interval [4,5] by using the bisection method. What happens on the interval [ 1 , 2] ? I wrote the code and everything seems fine with the interval [4,5] but for …