danieldot

Hi I am trying to connect and get a WebResponse of a CONNECTED user. For that, I should first connect to the webSite, but I can figure out how. I already read like 20 pages about cookies and stuff and still cant understand this stuff. The site im trying to …

hi guys, as part of my online game I need the server to always wait for variables that will come. I am using the "Socket s = myListener.Accpet...blabla.." the problem is that when I call Server.cs class the application freeze, 'cause its waiting for variables... I want it to listen …

Server [CODE]using System; using System.Collections.Generic; using System.ComponentModel; using System.Data; using System.Drawing; using System.Text; using System.Windows.Forms; using System.Net.Sockets; using System.Threading; using System.Net; namespace Server { public partial class Form1 : Form { private TcpListener tcpListener; private Thread listenThread; static NetworkStream clientStream; public Form1() { InitializeComponent(); this.tcpListener = new TcpListener(IPAddress.Any, 3000); this.listenThread …

Hello again guys, I am creating a board game, and I need for the begging to host an 10x10 array on server that will be access able for 2 clients. I dont know if the best way to do that is Server-Client or simply P2P.' I dont know any of …

Hi, I am coding a multiplayer board game, similiar to chess... I need to host an array 10x10 on the server and the client should be able to change things. Like a class with Get and Set, just accessable fron the Home network. I know nothing about this kind of …

Hello there, I got some strings of "x10" "x11" "x2" and stuff like that. Is there a way to take only the number from the string and convert it to int ? lets say [CODE]label1.Test = "x11";[/CODE] I want to take the 11 to some int.

I created 100 pictures boxes for my game with this code : [CODE] for (int p = 0; p <= 9; p++) { for (int o = 0; o <= 9; o++) { picsBoard[p, o] = new PictureBox(); picsBoard[p, o].Name = "emptyPicBox" + p.ToString() + "." + o.ToString(); picsBoard[p, o].Location …