But we still need to look into your code. May be there are some server settings isseu or some thing else

if the user can enter the article, bydefault set its article status as 0 and then let the admin to view all the articles from where he csn change the status and where you have to show the articles, you can select the articles like
select * from article where status = 1

manually run your query in mysql and then see what result it displays, and share it

its obvious you cannot, because you are echoing $branch in name tag :)

i commented [code]response.close()[/code]
because i was following an old tutorial.
please change this to [code]response.end()[/code]

pritaeas commented: Thanks for sharing. +14

it worked,
i changed my code to this
[CODE]var sys = require("util"),
http = require("http");

http.createServer(function(request, response) {
response.writeHead(200, {"Content-Type": "text/html"});
response.write("Hello World!");
//response.close();
}).listen(8090);

sys.puts("Server running at

try
[CODE]
<img src="img.jpg" onClick="window.open('http://www.daniweb.com')" />
[/CODE]
i think it should work fine

SolidSolutions commented: concise and kind. +5

[URL="

and there is no such extra ordinary thing in java which is not present in Php

Tofayel commented: I agree with you +0