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Hi, I have a doubt. Suppose we define a pointer or an array of pointers, and pass it to a function, as in like :- char *p; func(p); /*or this way*/ char *p[10]; /*and then pass this array somewhere to a fucntion*/ func(p); Here, in the call to the function, … 
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` Below Code not working :- #include<stdio.h> void main() { char *s; gets(s); printf("%c",s); } 
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why is the output of the below program is coming out as 'unequal' ??can anyone please explain?? #include<stdio.h> void func(char *); void main() { char *q; char *p; p="hello hii"; func(q); if(p==q) printf("equal"); else printf("unequal"); } void func(char *pi) { pi="hello hii"; } 
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Please refer to the code below.It is used to extract files from a given directory, for further processing. #include <dirent.h> #include <stdio.h> #include <string.h> int main(void) { int i=0; struct dirent *direntry; dir = opendir("E:/muzikk"); if(!dir) { printf("Error: directory did not open!\n"); return 1; } while((direntry=readdir(dir))!=NULL) { printf("%d %s\n",i,direntry->d_name); i++; …
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