Converting numbers to words

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can u cr8 me program that words converted to numbers.(1-50) using switch. pls help me.

Sure. Since your language's orthography apparently uses digits for any homonymous syllable, just use

(std::stringstream() << n).str()

pls post.

Sure. Since your language's orthography apparently uses digits for any homonymous syllable, just use

(std::stringstream() << n).str()

This gave me a good laugh.

plsss. i need it. can u make that program? i need it badly. pls

How do you convert numbers to words by hand? Take that algorithm and write it in C++.

Make a while loop to make a number (I called this one divisor) an multiply it by 10 till its larger than the number you're calculating.

Then in another loop, you're going to need to divide by divisor, get both the remainder AND the front digit and store them. Don't store them over n.

Then you're going to make a bunch of if statements to calculate the correct words based on the front (the current digit you're working on.) When I wrote it the total I have is 5 switch statements inside 4 if statements + some minor if statements to end the loop if there's errors or nothing else to calculate.

Here's my program:

#include <conio.h> 
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
 
char *make_words(char *s, int ncomma);
char *insert_comma(long n, int *ncomma);
char *int2words(int n);
int a;
 
int main(void)
{
 


 printf("Enter number: ");
 scanf("%d",&a);
  printf("%d = %s\n",a,int2words(a));

 
  getch();  
  return 0;
}

char *make_words(char *s, int ncomma)
{
  int i, len, rest = 0;
  char *p = NULL;
  static char zzz[256];
 
  static char *ones[] = {"one ","two ","three ","four ",
    "five ","six ","seven ","eight ","nine "};
  static char *tens[] = {"ten ","eleven ","twelve ","thirteen ",
    "fourteen ","fifteen ","sixteen ","seventeen ","eighteen ","nineteen "};
  static char *twenties[] = {"","twenty ","thirty ","forty ",
    "fifty ","sixty ","seventy ","eighty ","ninety "};
  static char *hundreds[] = {
    "hundred ","thousand ","million "};
 
  memset(zzz, '\0', 256);  // fill with nulls
  len = strlen(s);
  for(i = 0; i < len; i++)
  {
 
    if ((p = strchr((s[i] == ',') ? &s[++i] : &s[i], ',')) == NULL)
    {
      p = &s[strlen(s)];
    }
    if (s[i] == '0')
    {
      continue;  // skip one iteration
    }
    if ((rest = (p - &s[i])) != 0)
    {
      if (rest == 3)
      {
        strcat(zzz, ones[s[i] - '0' - 1]);
        strcat(zzz, hundreds[0]);

        if (len == 7 && s[2] == '0')  strcat(zzz, hundreds[1]);
        if (len == 11 && s[2] == '0')  strcat(zzz, hundreds[2]);
      }
      else if (rest == 2) 
      {
        if (s[i] == '1')
        {
          strcat(zzz, tens[s[++i] - '0']);
          rest--;
        }
        else
        {
          strcat(zzz, twenties[s[i] - '0' - 1]);
        }
      }
      else
        strcat(zzz, ones[s[i] - '0' - 1]);
    }
    if (rest == 1 && ncomma != 0)
    {
      strcat(zzz, hundreds[ncomma--]);
    }
  }
  return zzz;
}
 

char *insert_comma(long n, int *ncomma)
{
  static char zzz[30];
  int i = 0;
  char *p = &zzz[sizeof(zzz)-1];
 
  *p = '\0';
  *ncomma = 0;
  do 
  {
    if (i % 3 == 0 && i != 0) 
    {
      *--p = ',';
      ++*ncomma;
    }
     *--p = (char)('0' + n % 10);
    n /= 10;
    i++;
  } while(n != 0);
  return p;
}
 
char *int2words(int n)
{
  int nc;
  char *ps, *zzz, *minus;
  char *buffer;
  buffer = (char *) malloc(256);
 
  // save any - sign
  if (n < 0)
  {
    minus = "minus";
    n = abs(n);
  }
  else
  {
    minus = "";
  }
 
  ps = insert_comma(n, &nc);

  zzz = make_words(ps, nc);
 
  sprintf(buffer,"%s %s", minus, zzz);
 
  return buffer;
  getch();
}

# include <stdio.h>
void main () {

Int N;

printf("Input number:");
scanf("%d",&N);
if
(N==1){
printf("One");
}
else if
(N==2){
printf("Two");
}
else {
printf("Invalid")
}

}

why don't you used else if?
its good but super basic...