verifying a value IS NOT in a table

[Fost]

Hi guys, Im working on a bit of MySQL and was wondering if there is a way (without using php arrays or other) to search a table for a value (say 1) and return the rows which '1' wasnt found in. != wont work because the table contains more than one value.

In summary, i want to return the rows which a value isnt found in.

My applogies if this doesnt make sense, if youd like any more, just ask.

Fost

[varmadba]

you can use full-text search if avaliable

select *
from table
where description not like ‘%1%’

or
to search in all the rows

select *
from table
where not exists(*, ‘1”’)

or you do dont have full text search avaliable you can go with function

not like
not exists

[tesuji]

It depends on the data type of the attribute you demand to be excluded from result set, for examples

if numeric: ... where Attribute != number
if char: ...where Attribute != 'excludeme'
if char surrounded with other stuff: ... where Attribute NOT LIKE '%excludeme%'
if NULL ... where Attribute IS NOT NULL

if to exclude a set, for example a set of single char values:
... where Attribute NOT IN ('1', '2', ...)

There is also ANY, SOME, ALL, EXISTS, but this is just another thing.