Hi, i've been trying to make a simple login script php and have come across these error messages
Notice: Undefined variable: pass in /var/www/vhosts/numyspace.co.uk/web_users/home/~unn_t013534/public_html/adminlog.php on line 15
Warning: mysql_num_rows(): supplied argument is not a valid MySQL result resource in /var/www/vhosts/numyspace.co.uk/web_users/home/~unn_t013534/public_html/adminlog.php on line 18
The code i've used so far is:
<form name = "adminlog"
id = "adminlog" method = "post"
action = "adminlog.php">
Username:
<input type = "text"
name = "username" id = "username" />
Password:
<input type = "password"
name = "pass" id = "pass" />
<input type = "submit" value = "Log In" />
</form>and:
<?php
$username = $_POST['username'];
$password = $_POST['pass'];
include'database_conn.php';
$sql="SELECT * FROM userlog WHERE username='$username and password='$pass'";
$result=mysql_query($sql);
$count=mysql_num_rows($result);
if($count==1){
echo "Welcome";
}
else {
echo "Wrong Username or Password";
}
?>