PHP/MySQL INSERT INTO Multiple Tables from Forms

[kanoy83]

hi guys,

am trying to make a simple PHP form submission and insert some data to MySQL, my tables are:

category:
-id
-category_name

table1:
-category_id(FK)
-title
-description

table2:
-table1_id(FK)
-filetype
-filesize
-filedate
-filename

Form:
-Date
-Title
-description
-category(drop down)
-upload file (get the file info like type,ext,size,filename)

Or is there any sample script or similar project, it would be a great help. Thanks! Cheers!

[kanoy83]

to make it short, heres the code:

Form:

<strong>Fill up the form:</strong><br /><br>                

    <form enctype="multipart/form-data" action="upfileone.php" method="POST">
        Date: <?php echo date("d-M-Y") ?>

            <p>Title:
                <input type="text" name="title" value="<?php echo $sel_filepage['file_title']; ?>" id="file_title" />
            </p>

            <p>Description:<br>
                <textarea name="description" rows="4" cols="24">
                <?php echo $sel_filepage['content']; ?></textarea>
            </p>

        Category:
        <select name="select_cat">
        <?php $cat_set = get_all_categs();
            while($category = mysql_fetch_array($cat_set)){
                $catname = $category['cat_name'];
                echo '<option value="'.$catname.'">'.$catname.'</option>';
            }
        ?>
        </select>
        <br><br>
        <label for="file">Choose File to Upload:</label>
        <input type="file" name="upfile" id="upfile" > <br /><br />
        <input type="hidden" name="MAX_FILE_SIZE" value="1000000" />
        <input type="hidden" name="filepage" value="<?php echo $_GET['filepage']?>">
        <input type="submit" name="upload" value="Add" class="pure-button pure-button-success">
        <a href="content.php?filepage=<?php echo $sel_filepage['id']; ?>" class="pure-button">Cancel</a>
    </form> <!-- END FORM -->

Action FILE:

<?php
require_once("includes/functions.php");

// directory to be saved
$target = "server/php/files/";
$target = $target . basename($_FILES['upfile']['name']);

// gets info from FORM
$currentDate = date("Y-m-d");
$file_title = $_POST['title'];
$content = $_POST['description'];
$category = $_POST['select_cat'];
$upfile = ($_FILES['upfile']['name']);

// connects to db
$con = mysqli_connect("localhost", "root", "password", "database");
if(mysqli_connect_errno())
{
    echo "error connection" . mysqli_connect_error();
}

// insert to database
$sql = "INSERT INTO filepages (category_id,file_title,content)
VALUES ('$category','$file_title','$content')";

/*$sql2 = "BEGIN
            INSERT INTO filepages (category_id, file_title, content)
                VALUES ('$category','$file_title','$content')
            INSERT INTO fileserv (file_date)
                VALUES ($currentDate)
            COMMIT";*/

if(!mysqli_query($con, $sql))
{
    die('Error ' . mysqli_error());
}
echo "1 File Added <br>";

    if (file_exists("server/php/files/" . $_FILES["upfile"]["name"]))
      {
      echo $_FILES["upfile"]["name"] . " already exists. ";
      }
    else
      {
        insertFile( $_POST['filepage'], 
                    $_FILES["upfile"]["type"], 
                    ($_FILES["upfile"]["size"] / 1024), 
                    $_FILES["upfile"]["name"]);       
        move_uploaded_file($_FILES["upfile"]["tmp_name"],"server/php/files/" . $_FILES["upfile"]["name"]);

        echo "The FILE " . basename($_FILES['upfile']['name']) . " has been uploaded.<br>";
        echo "Stored in: " . "server/php/files/" . $_FILES["upfile"]["name"] . "<br>";
        echo "Upload: " . $_FILES["upfile"]["name"] . "<br>";
        echo "Type: " . $_FILES["upfile"]["type"] . "<br>";
        echo "Size: " . ($_FILES["upfile"]["size"] / 1024) . " kB<br>";
        echo "Temp file: " . $_FILES["upfile"]["tmp_name"] . "<br>";

      }



?>

It does insert to both tables, now my main problem is:

1. how to get the ID from drop down menu of category and insert to Filepages.category_id
2. how to get Filepages.ID data and insert to Fileserve

Thanks!

[kanoy83]

i hope someone can help me :(

[kanoy83]

JUST FOR CLARIFICATION:

i have simple form submission with title, description and file upload, this file having size,type,filename will insert to table3, ALL same time after ADD.

am trying to make a simple PHP form submission and insert data to 3 MySQL tables:

category:
-id
-category_name (for dropdown menu)

table1:
-id
-category_id (FK, automatic when dropdown selected) NOT WORKING
-title
-description

table2: (automatic insert file properties info here)
-id // auto increment
-table1_id (FK, automatic get ID from table1) NOT WORKING
-filetype
-filesize
-filedate
-filename

FORM:
-Date
-Title
-description
-category(drop down)
-upload file (get the file info like type,ext,size,filename)

Status: it is inserting but only 2 not working

I think this is simple, maybe either mysql statement or handling of php data?

Please help, cheers

[kanoy83]

hi guys, hope u can help :(

any clue,hint,or guide will be very helpful?

thanks again

[pritaeas]

1. If you give the dropdown values the ID of the category, then you can use that directly from the POST array.

2. Not sure what you mean, can you explain?

[kanoy83]

categs
----------------
+ id | catname + 
================
+ 1  | fruit   +
+ 2  | animal  +
----------------

filepages
-----------------------------------------
| id | categoryid | file_title | content
=========================================
| 1  | (empty)    | bear       | brown  |
| 2  | (empty)    | apple      | red    |
-----------------------------------------

fileserv
-----------------------------------------------------------------------
| fileid | filepage_id | filetype | filesize | filename  | filedate  |
=======================================================================
| 1      | (empty)     | jpeg     | 89       | apple.jpg | 08-03-2013 |
| 2      | (empty)     | jpeg     | 120      | bear.jpg  | 08-03-2013 |

the posted currently is similar with my basic upload file but only have 1 table and insert category NAME not ID but this one doesnt work because it is requiring category ID