If there are two arrays
arr1[]={1,4,5,6}
arr2[]={1,5}
I want to get the output as arr[]={4,6} i.e i have to remove all the common elements that arr1 and arr2 have and printing the required output . Can any one give me the program in C++ for this with normal looping techniques?
Jump to PostThis shud do.
#include<iostream.h> #include<conio.h> void main() { int a[10],b[10],i,j,flag=0; cout<<"\n Enter the elements of array 1"; for(i=0;i<4;i++) cin>>a[i]; cout<<"\n Enter the elements of array 2"; for(j=0;j<2;j++) cin>>b[j]; for(i=0;i<4;i++) { flag=0; for(j=0;j<2;j++) if(a[i]==b[j]) flag++; if(!flag) cout<<a[i]<< " "; } getch(); }
This shud do.
#include<iostream.h>
#include<conio.h>
void main()
{
int a[10],b[10],i,j,flag=0;
cout<<"\n Enter the elements of array 1";
for(i=0;i<4;i++)
cin>>a[i];
cout<<"\n Enter the elements of array 2";
for(j=0;j<2;j++)
cin>>b[j];
for(i=0;i<4;i++)
{
flag=0;
for(j=0;j<2;j++)
if(a[i]==b[j])
flag++;
if(!flag)
cout<<a[i]<< " ";
}
getch();
}The other option is to just sort both arrays which will make traversing the arrays and finding non-duplicates much easier.
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