Help converting an if loop into a while loop?

Question

camigirl4k3 0 Newbie Poster

14 Years Ago

the program I had looks like this:

def wordToNumber(word):
if word == "one":
return 1
elif word == "two":
return 2
elif word == "three":
return 3
elif word == "four":
return 4
elif word == "five":
return 5
elif word == "six":
return 6
elif word == "seven":
return 7
elif word == "eight":
return 8
elif word == "nine":
return 9
elif word == "ten":
return 10

but since my professor is hella strict he's like...yes that works...but I'd like it in a while loop.

the .....monstrosity....that I've come up with so far that I know is completely wrong but bear with me im learning...and he's not that great of a teacher....

def wordToNumber(word):
wordList = ["zero","one","two","three",...,"nine"]
while word in wordList:
wordList == range(10)
print i in range(10)

:D...aha....yeah I know. fail....but all I need is someone to show me the proper way and then maybe i can learn not to be such a fail....lol.

please help me?

convert loop python

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10 Replies
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Latest Post 13 Years Ago Latest Post by TrustyTony

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Kruptein 15 Posting Whiz in Training

14 Years Ago

In your case it's actually much easier to use:

def wordtonum(word):
    wordList = ["zero","one","two","three","four","five","six","seven","eight","nine"]
    return int(wordList.index(word))

Edited 14 Years Ago by Kruptein because: n/a

vegaseat 1,735 DaniWeb's Hypocrite

14 Years Ago

camigirl4k3,
you got to learn to use the necessary indentations with your statement blocks.

Kruptein 15 Posting Whiz in Training

14 Years Ago

camigirl4k3,
you got to learn to use the necessary indentations with your statement blocks.

The indentations are maybe changed because camigirl4k3 doesn't use code tags

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vegaseat 1,735 DaniWeb's Hypocrite Team Colleague · Answer 1 · 2010-03-06T22:07:07+00:00

If indentations were used, you can see them by temporarily going to reply. In this case no code indentations at all.

Tech B 48 Posting Whiz in Training · Answer 2 · 2010-03-07T00:07:00+00:00

So what is the program supposed to do? Are you supposed to input a number and get the word form of the number? Or input the word and get the integer it represents?
And incase you didn't know the code tags they are [COD'E] [/COD'E] with out the ' in them.

this is code......

Kruptein 15 Posting Whiz in Training · Answer 3 · 2010-03-07T01:54:55+00:00

So what is the program supposed to do? Are you supposed to input a number and get the word form of the number? Or input the word and get the integer it represents?
And incase you didn't know the code tags they are [COD'E] [/COD'E] with out the ' in them.
this is code......

I think he means that you have to pass a word and convert it in an integer.

just like my code does ...

Tech B 48 Posting Whiz in Training · Answer 4 · 2010-03-07T04:36:07+00:00

But like your code, if I don't search for a word that is in the list, it gives ne an index error. That's not converting anything, just spitting out the same word. I was thinking like the integer 10 to "ten"

Kruptein 15 Posting Whiz in Training · Answer 5 · 2010-03-07T16:05:18+00:00

But like your code, if I don't search for a word that is in the list, it gives ne an index error. That's not converting anything, just spitting out the same word. I was thinking like the integer 10 to "ten"

Okay if U give a number in words larger then nine it will throw an error,
but I just used the same example as the topic starter.

the thing you ask is the reverse, if U want that you have to do:

def numtoword(num):
    wordlist=["zero","one","two","three","four","five","six","seven","eight","nine"]
    if int(num)>len(wordlist):
        print "sorry that number is not in the list"
    else:
        return wordlist[int(num)]

glog17 0 Newbie Poster · Answer 6 · 2010-04-29T15:18:09+00:00

document.write("<center>FIBONACCI</center>")
var f1=prompt("Enter NUmber From 1 to 19: ","0");

if(f1=='1')
(document.write("<center>1 based number</center>"));
if(f1=='2')
(document.write("<center>1+1 = 2</center>"));
if(f1=='3')
(document.write("<center>1+1+2 = 4</center>"));
if(f1=='4')
(document.write("<center>1+1+2+3 = 7</center>"));
if(f1=='5')
(document.write("<center>1+1+2+3+4 = 11</center>"));
if(f1=='6')
(document.write("<center>1+1+2+3+4+5 = 16</center>"));
if(f1=='7')
(document.write("<center>1+1+2+3+4+5+6 = 22</center>"));
if(f1=='8')
(document.write("<center>1+1+2+3+4+5+6+7 = 29</center>"));
if(f1=='9')
(document.write("<center>1+1+2+3+4+5+6+7+8 = 37</center>"));
if(f1=='10')
(document.write("<center>1+1+2+3+4+5+6+7+8+9 = 46</center>"));
if(f1== '11')
(document.write("<center>1+1+2+3+4+5+6+7+8+9+10 = 56</center>"));
if(f1== '12')
(document.write("<center>1+1+2+3+4+5+6+7+8+9+10+11 = 67</center>"));
if(f1== '13')
(document.write("<center>1+1+2+3+4+5+6+7+8+9+10+11+12 = 79</center>"));
if(f1== '14')
(document.write("<center>1+1+2+3+4+5+6+7+8+9+10+11+12+13 = 92</center>"));
if(f1== '15')
(document.write("<center>1+1+2+3+4+5+6+7+8+9+10+11+12+13+14 = 106</center>"));
if(f1== '16')
(document.write("<center>1+1+2+3+4+5+6+7+8+9+10+11+12+13+14+15 = 121</center>"));
if(f1== '17')
(document.write("<center>1+1+2+3+4+5+6+7+8+9+10+11+12+13+14+15+16 = 137</center>"));
if(f1== '18')
(document.write("<center>1+1+2+3+4+5+6+7+8+9+10+11+12+13+14+15+16+17 = 154</center>"));
if(f1== '19')
(document.write("<center>1+1+2+3+4+5+6+7+8+9+10+11+12+13+14+15+16+17+18+ = 172</center>"));
</script>
</body>
</html>

Editor's note:
Wrong forum!

TrustyTony 888 pyMod Team Colleague Featured Poster · Answer 7 · 2010-04-29T17:03:06+00:00

Some problem with your function included down. Strange, the printed message comes only from calling the function from command line, not in loop going over range.

>>> numtoword('11')
sorry that number is not in the list
>>> ================================ RESTART ================================
>>> 
----------
-1 nine
0 zero
1 one
2 two
3 three
4 four
5 five
6 six
7 seven
8 eight
9 nine
10

Traceback (most recent call last):
  File "D:/Tony/numtoword.py", line 27, in <module>
    print i,numtoword(i)
  File "D:/Tony/numtoword.py", line 12, in numtoword
    return wordlist[int(num)]
IndexError: list index out of range
>>>

After limiting range until 9 for that loop (range(-1,10))

>>> 
----------
-1 nine
0 zero
1 one
2 two
3 three
4 four
5 five
6 six
7 seven
8 eight
9 nine
----------
-1 None
0 zero
1 one
2 two
3 three
4 four
5 five
6 six
7 seven
8 eight
9 nine
10 ten
11 eleven
----------
-1 None
0 nolla
1 yksi
2 kaksi
3 kolme
4 neljä
5 viisi
6 kuusi
7 seitsemän
8 kahdeksan
9 ykdeksän
----------
>>>

Here is my version numtoword2 after your old version

# -*- coding: latin1 -*-
english=["zero","one","two","three","four","five","six","seven","eight","nine","ten","eleven"]
finnish=["nolla","yksi","kaksi","kolme","neljä","viisi","kuusi","seitsemän","kahdeksan","ykdeksän"]

languages=[english,finnish]

def numtoword(num):
    wordlist=["zero","one","two","three","four","five","six","seven","eight","nine"]
    if int(num)>len(wordlist):
        print "sorry that number is not in the list"
    else:
        return wordlist[int(num)]

def numtoword2(num):
    if num in range(len(wordlist)):
        return wordlist[int(num)]
##    else:
##        return '****'
##        return -1
##        raise IndexError,str(num)+" not in proper range (0.."+str(len(wordlist))+')'

print '-'*10

## we do not know how many words the function knows (local variable)

## range starting from -1 just to test misuse of function

for i in range(-1,10):     ##range(-1,11):
    print i,numtoword(i)

print '-'*10

for wordlist in languages:
    for i in range(-1,len(wordlist)):
        print i,numtoword2(i)
    print '-'*10

Help converting an if loop into a while loop?

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