problem with shortest common supersecuence

[chouki]

hello
I'm trying to make a program
that allows you to return and calculate the shortest common supersecuence using dynamic programming.
The basic ideas of supersecuence common Shortest
to search a given set of strings for example L, the smallest chain, which is one for each string supersecuence L.
the problem I have not returned to me or the chain or the length
well I do not know what is going wrong I attached what I have done so far.
/ / Fill the array using prog.dinámica:

private int aux[][];
                               int longr = r.length();
	                int longt = t.length();
		aux = new int[longr + 1][longt + 1];

		for (int i = 0; i <= longr; i++) {
			m[i][0] = i;
			aux[i][0] = -1;
		}

		for (int j = 0; j <= longt; j++) {
			m[0][j] = j;
			aux[0][j] = 1;
		}

		for (int j = 1; j <= longt; j++) {
			for (int i = 1; i <= longr; i++) {

		if (r.charAt(longr - i) ==  t.charAt(longt - j)) {
					m[i][j] = m[i - 1][j - 1] + 1;
					aux[i][j] = 0;
				} else {

					m[i][j] = Math.min(m[i - 1][j], m[i][j - 1]) + 1;
					if (m[i - 1][j] <= m[i][j - 1]) {
						aux[i][j] = -1;
					} else {
						aux[i][j] = 1;
					}
				}

			}
		}
	}

method returns the string i thkink it's wrong

public String unaSolución() {
		int lonr = r.length(), lonj = t.length();
		int i = r.length(), j = t.length();
		String cad = "";
		while (i > 0 || j > 0) {
			if (aux[i][j] == 0) {
				cad = cad + r.charAt(lonr - i);
				i = i - 1;

				j = j - 1;

			} else if (aux[i][j] == -1) {
				cad = cad + r.charAt(lonr - i);
				i = i - 1;
			} else {
				cad = cad + t.charAt(lonj - j);
				j = j - 1;
			}
		}

		return cad;
	}

In anticipation of your help
Yours sincerely
thank u

[dsmush]

Good luck in finding help as you won't get it here people are too of themselves to help us :(. Try a more helpful forum like dream.in.code :)

[chouki]

Good luck in finding help as you won't get it here people are too of themselves to help us :(. Try a more helpful forum like dream.in.code :)

thank u