how will i make the histogram chart in vertical orientation

[csha_cs508]

our task is to show the histogram in a vertical orientation like this:

Sample Input/Output
Enter a string: waka waka fifa
Histogram for waka waka fifa
*
*
* * * *
* * * * *
a f i k w

I have here my code, but the output of this is in horizontal orientation.. what am i going to do to make this vertical? the sanple output of this is:

Sample Input/Output
Enter a string: waka waka fifa
Histogram for waka waka fifa
a * * * * *
f * *
i *
k * *
w * *

# include <iostream>
# include <string>
using namespace std;
main()
{ 
  string letters="abcdefghijklmnopqrstuvwxyz";
  string sentence;
  string::size_type slen;
  int name[26];
  char ans;

do{  
  for(int s=0; s < 26; s++)
    name[s] = 0;
  
  cout<<"Enter a string (no space please): ";
  cin>>sentence;
  cout<<endl;
  cout<<"Histogram for "<<sentence<<endl;
  
//  slen = sentence.length();
  
  for(int t=0; t<26; t++){
    for(int sl=0; sl<slen; sl++){
      if (letters[t] == sentence[sl])
        name[t]++;
    }
  }
  
  for (int r=0; r < 26; r++){
    if (name[r] > 0){
      cout<<letters[r]<<" ";
    for(int i=0; i <name[r]; i++)
      cout<<"*";
    cout<<endl;
    } 
  } 
  
      cout << endl << "another? [y/n]: ";
      cin >> ans; 
      cout<<endl;
       
}while(ans != 'n'); 


      cout<<"\n\nPress any key and ENTER to EXIT! ";         
      char response;
      cin>>response;
      
      return 0;
}

[jonsca]

You have a set number of lines corresponding to the maximum number. If the count in your int array exceeds a certain criteria print a star, doing this for each index of the array. Take a stab at it, you'll probably come pretty close and post back if you have problems.

[mike_2000_17]

From looking at the original problem, it may be required, and it makes the "drawing vertically" problem a bit easier, to sort from most often occurring letter to least occurring letter. But as jonsca said you can do it without sorting too.

[jonsca]

I was able to do it just using the maximum of the data set but sorting certainly works for that too. Someone gave the OP a turnkey solution in one of his other threads :( (I did not test it) so we'll see what he/she reports back.