Hi, i have a problem in displaying the added value of two numbers.
I know how to convert the input number into decimal.
So after converting it, i added those value and got it stored in a register.
My problem is how can I display if the sum is like 10, 11 , 12 ,13 ...onwards.
It will display like ?,@,A,B.
Can someone help me on how to display the right number?
Jump to PostUm, where do you want it displayed? On a billboard, command prompt, in the sky, DOS, in the dirt, windows? What OS does this display device use?
Jump to PostIm using tasm xD
In command prompt.
what i mean is everytime i want to display it, it display the @,?,A,B,C etc. when the sum exceeds to 10,11,12,13,14 etcInstead of explaining what you meant, had you posted your code here, you may have already got the solution.
Jump to PostI had written a procedure for displaying integers on the screen a while back, this might help you with your problem.The code is full of comments so I hope you'll not have a hard time figuring out what it does.
put_num: ;function put_num: prints value stored in …
Um, where do you want it displayed? On a billboard, command prompt, in the sky, DOS, in the dirt, windows? What OS does this display device use?
Im using tasm xD
In command prompt.
what i mean is everytime i want to display it, it display the @,?,A,B,C etc. when the sum exceeds to 10,11,12,13,14 etc
Im using tasm xD
In command prompt.
what i mean is everytime i want to display it, it display the @,?,A,B,C etc. when the sum exceeds to 10,11,12,13,14 etc
Instead of explaining what you meant, had you posted your code here, you may have already got the solution.
Here is the example code
mov ah, 1
int 21h ; to get a single number input from the user
sub al, 30h ; to make the input number to decimal
mov a, al ; move the content of al to a variable
mov ah, 1
int 21h
sub al, 30h
add al, a ; add the contents of al and a
add al, 30h
mov ah, 2
mov dl, al ; to display the content of al
int 21hhere's the problem, when the sum reaches 10 or higher, it will not display 10 but instead the next symbol in the ascii table after the 9. how can i display it?
I had written a procedure for displaying integers on the screen a while back, this might help you with your problem.The code is full of comments so I hope you'll not have a hard time figuring out what it does.
put_num: ;function put_num: prints value stored in the ax register
;(a 16 bit integer) to stdout
push ax ;save registers
push bx
push cx
push dx
xor cx,cx ;cx=0
mov bx,10d ;bx=10(decimal)
PNloop1:xor dx,dx ;dx=0
div bx ;dx=ax/bx
push dx ;push the result in stack
inc cx ;cx++(cx acts like a counter to notify how many digits in the number)
cmp ax,0 ;but if the ax was zero,
jnz PNloop1 ;then jump to PNloop1
mov ah,2 ;otherwise...(Dos function to print a character)
PNloop2:pop dx ;get the value just pushed in to the stack in dx,
add dl,48 ;convert it in to ascii
int 21h ;and print it
dec cx ;decrease counter
jnz PNloop2 ;if cx not zero (still digits left) then loop again.
;otherwise ..
pop dx ;restore registers and return
pop cx
pop bx
pop ax
retI tried the given code, but it displays tons of 5 @___@.
here is my complete code
title add.asm
dosseg
.model small
.stack 0100h
.data
t1 db,10,13, "Enter a number: $"
t2 db "The sum is: $"
a db ?
b db ?
.code
mov dx, @data
mov ds, dx
mov ah, 9
lea dx, t1
int 21h
mov ah, 1
int 21h
sub al, 30h
mov a, al
mov ah, 1
int 21h
sub al, 30h
add al, a
push ax
push bx
push cx
push dx
xor cx, cx
mov bx, 10d
pnloop1:
xor dx,dx
div bx
push dx
inc cx
cmp ax, 0
jnz pnloop1
mov ah, 2
pnloop2:
pop dx
add dl, 48d
int 21h
dec cx
jnz pnloop1
pop dx
pop cx
pop bx
pop ax
mov ax, 4c00h
int 21h
endIt's a procedure, just call it from your main program like this:
.model small
.stack 100h
.data
a db 0
.code
start:
mov ax,@data
mov ds,ax
mov ah, 1
int 21h ; to get a single number input from the user
sub al, 30h ; to make the input number to decimal
mov a, al ; move the content of al to a variable
mov ah, 1
int 21h
sub al, 30h
add al, a ; add the contents of al and a
xor ah,ah ;ah=0
call put_num
mov ah,4ch
int 21h
put_num: ;function put_num: prints value stored in the ax register
;(a 16 bit integer) to stdout
push ax ;save registers
push bx
push cx
push dx
xor cx,cx ;cx=0
mov bx,10d ;bx=10(decimal)
PNloop1:xor dx,dx ;dx=0
div bx ;dx=ax/bx
push dx ;push the result in stack
inc cx ;cx++(cx acts like a counter to notify how many digits in the number)
cmp ax,0 ;but if the ax was zero,
jnz PNloop1 ;then jump to PNloop1
mov ah,2 ;otherwise...(Dos function to print a character)
PNloop2:pop dx ;get the value just pushed in to the stack in dx,
add dl,48 ;convert it in to ascii
int 21h ;and print it
dec cx ;decrease counter
jnz PNloop2 ;if cx not zero (still digits left) then loop again.
;otherwise ..
pop dx ;restore registers and return
pop cx
pop bx
pop ax
ret
end startNote that the above is a masm code.
Thanks alot ! it works :DDDDD Thank you! :DDDDDD
heres the final code in TASM :D
.model small
.stack 100h
.data
a db 0
t1 db,10,13, "Enter a number: $"
t2 db,10,13, "The sum is: $"
.code
main proc
mov ax,@data
mov ds,ax
mov ah, 9
lea dx, t1
int 21h
mov ah, 1
int 21h ; to get a single number input from the user
sub al, 30h ; to make the input number to decimal
mov a, al ; move the content of al to a variable
mov ah, 9
lea dx, t1
int 21h
mov ah, 1
int 21h
sub al, 30h
add al, a ; add the contents of al and a
push ax
mov ah, 9
lea dx, t2
int 21h
pop ax
xor ah,ah ;ah=0
call put_num
mov ah,4ch
int 21h
main endp
put_num proc ;function put_num: prints value stored in the ax register
;(a 16 bit integer) to stdout
push ax ;save registers
push bx
push cx
push dx
xor cx,cx ;cx=0
mov bx,10d ;bx=10(decimal)
PNloop1:xor dx,dx ;dx=0
div bx ;dx=ax/bx
push dx ;push the result in stack
inc cx ;cx++(cx acts like a counter to notify how many digits in the number)
cmp ax,0 ;but if the ax was zero,
jnz PNloop1 ;then jump to PNloop1
mov ah,2 ;otherwise...(Dos function to print a character)
PNloop2:pop dx ;get the value just pushed in to the stack in dx,
add dl,48 ;convert it in to ascii
int 21h ;and print it
dec cx ;decrease counter
jnz PNloop2 ;if cx not zero (still digits left) then loop again.
;otherwise ..
pop dx ;restore registers and return
pop cx
pop bx
pop ax
ret
put_num endp
endThanks alot ! it works :DDDDD Thank you! :DDDDDD
heres the final code in TASM :D
.model small .stack 100h .data a db 0 t1 db,10,13, "Enter a number: $" t2 db,10,13, "The sum is: $" .code main proc mov ax,@data mov ds,ax mov ah, 9 lea dx, t1 int 21h mov ah, 1 int 21h ; to get a single number input from the user sub al, 30h ; to make the input number to decimal mov a, al ; move the content of al to a variable mov ah, 9 lea dx, t1 int 21h mov ah, 1 int 21h sub al, 30h add al, a ; add the contents of al and a push ax mov ah, 9 lea dx, t2 int 21h pop ax xor ah,ah ;ah=0 call put_num mov ah,4ch int 21h main endp put_num proc ;function put_num: prints value stored in the ax register ;(a 16 bit integer) to stdout push ax ;save registers push bx push cx push dx xor cx,cx ;cx=0 mov bx,10d ;bx=10(decimal) PNloop1:xor dx,dx ;dx=0 div bx ;dx=ax/bx push dx ;push the result in stack inc cx ;cx++(cx acts like a counter to notify how many digits in the number) cmp ax,0 ;but if the ax was zero, jnz PNloop1 ;then jump to PNloop1 mov ah,2 ;otherwise...(Dos function to print a character) PNloop2:pop dx ;get the value just pushed in to the stack in dx, add dl,48 ;convert it in to ascii int 21h ;and print it dec cx ;decrease counter jnz PNloop2 ;if cx not zero (still digits left) then loop again. ;otherwise .. pop dx ;restore registers and return pop cx pop bx pop ax ret put_num endp end
you're welcome.
And also mark this thread solved.
how can i mark this thread as sovled? ><
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