How to find lowest number?

[Hussam Alahmadi]

Hi every body

i have a Question

How to find lowest number?

this my code

is there any mistake ?

import java.util.Scanner;


public class MaxNumber {

public static void main(String[] args) {
Scanner input = new Scanner(System.in);
int min = 0 ; int count=1;

System.out.println("Enter a number : ");
int num=input.nextInt();

for(;;){
if(num==0)
break;

if(num<=min){
num=min;
count=0;
}
if (num==min)
count++;

System.out.println("Enter a number : ");
num=input.nextInt();

}
System.out.println("The min number is : " + min );

System.out.println("The occurrence count of the min number is : " +  count);
}
}

[JamesCherrill]

if(num<=min){
  num=min;
  count=0;
}

You start with min=0, so how often will num be less that that?

for(;;){
   if(num==0)
      break;
   ...

I see what you intended here, but the more usual way to code that is

while(num != 0) {
   ...

And finally, indenting your code will make it much easier to read and debug.

[Hussam Alahmadi]

can you write it in code?

because i do not understand

[JamesCherrill]

This is your homework, so you must write the code.
You hve a problem with
if(num<=min){
min is 0, so num will never be less than min

[Hussam Alahmadi]

thank you it's work now

[nHulk]

import java.util.Scanner;
     
     
    public class MaxNumber {
     
    public static void main(String[] args) {
    Scanner input = new Scanner(System.in);
    int min = 0 ; int count=1;
     System.out.println("Enter a number : ");
    int num=input.nextInt();
    min=num;
    for(;;)
  {

    if(num==0)
     break;
     
    if(num<=min)
    {
    min=num;
    count=0;
    }
    
     System.out.println("Enter a number : ");
     num=input.nextInt();
     
        
    }

    System.out.println("The min number is : " + min );
     
    }
    }

thank you it's work now