run() placed inside main() is a problem. Why?

[rahul.ch]

Two doubts:
1. Placing run() inside main() generates "illegal start of expression error"? So why can't run() be placed inside main()?

2.With the above code I am getting the output as A C D B. Why B comes last is because of join(). But what I'm unable to understand is that on invoking start() shouldn't run() get called immediately thus generating the output as C D A B?

Help please..Thanks

[JamesCherrill]

1. You can't define one method inside another - that's just the Java langauge definition. (except when the second method is inside an inner class defined inside a method...)
2. After executing t.start()) you have two threads withe same priority and no synchronisation, so you have no control or knowledge about the order in which they will be executed.

[rahul.ch]

Oh great that makes it much more clear :)