How to create menu in this code, case menu option example 1.sum each row et

[diknas]

#include <conio.h>
#include <iostream>

using namespace std;

int main()
{
int A[10][10],m,n,x,y,sum=0;
//Create a Matrix 
cout << "Enter number of rows and columns in Matrix A : \n";
cin>>n>>m;
cout << "Enter elements of Matrix A : \n";
for(x=1;x<n+1;++x)
for(y=1;y<m+1;++y)
cin>>A[x][y];
//Find sum of each row
for(x=1;x<n+1;++x)
{
A[x][m+1]=0;
for(y=1;y<m+1;++y)
A[x][m+1]=A[x][m+1]+A[x][y];
}
//Find sum of each column
for(y=1;y<m+1;++y)
{
A[n+1][y]=0;
for(x=1;x<n+1;++x)
A[n+1][y]+=A[x][y];
}
cout << "\nMatrix A, Row Sum (Last Column)" << " and Column Sum (Last Row) : \n";
for(x=1;x<n+1;++x)
{
for(y=1;y<m+2;++y)
cout << A[x][y] << "     ";
cout << "\n";
}
//Print sum of each column
x=n+1;
for(y=1;y<m+1;++y)
cout << A[x][y] << "     ";
cout << "\n";
if(m==n)
{
for(x=1;x<m+1;x++)
for(y=1;y<n+1;y++)
if(x==y)
sum+=A[x][y];
else
if(y==m-(x+1))
sum+=A[x][y];
}
cout << "Sum of diagonal elements is : " << sum << endl;
getch();
return 0;
}

[diknas]

How to add the menu case option for that code? example: 1.Sum Row
                                                        2.Sum column
                                                        3.Diagonal sum
                                                        4.exit
      please help me :)                                                

[phorce]

Hey,

I'll give you an example.. Then you can just relevant insert the code where you need it.

int choice = 0;

    cout << "Please enter an option: \n";
    cout << "\t\t 1) Sum Row\n";
    cout << "\t\t 2) Sum Column\n";
    cout << "\t\t 3) Diagonal Sum\n";
    cout << "\t\t 4) Quit\n";
    cin >> choice;

    switch(choice)
    {
        case 1:
         // Sum row code
        break;

        case 2:
         // Sum col row
        break;

        case 3:
          // diagonal sum
        break;

        case 4:
            // quite
            return 0;
        break;

        default:
          cout << "Option unknown";
        break;

    }

Dunno if that will help you at all

[diknas]

thanks in advance has answered my question :), I've input all, is it true the code like the below???
, and I got an error messages "6 D:\Dev-Cpp\Untitledp.cpp expected unqualified-id before '{' token" , how can I fix it?

#include <conio.h>
#include <iostream>

using namespace std;
int choice = 0;
{
cout << "Please enter an option: \n";
cout << "\t\t 1) Sum Row\n";
cout << "\t\t 2) Sum Column\n";
cout << "\t\t 3) Diagonal Sum\n";
cout << "\t\t 4) Quit\n";
cin >> choice;
switch(choice)
{
case 1:
// Sum row code

cout << "Enter number of rows and columns in Matrix A : \n";
cin>>n>>m;
cout << "Enter elements of Matrix A : \n";
for(x=1;x<n+1;++x)
for(y=1;y<m+1;++y)
cin>>A[x][y];

for(x=1;x<n+1;++x)
{
A[x][m+1]=0;
for(y=1;y<m+1;++y)
A[x][m+1]=A[x][m+1]+A[x][y];
}
break;

case 2:
// Sum col row
for(y=1;y<m+1;++y)
 {
A[n+1][y]=0;
for(x=1;x<n+1;++x)
A[n+1][y]+=A[x][y];
}
cout << "\nMatrix A, Row Sum (Last Column)" << " and Column Sum (Last Row) : \n";
for(x=1;x<n+1;++x)
{
for(y=1;y<m+2;++y)
cout << A[x][y] << "     ";
cout << "\n";
}
x=n+1;
for(y=1;y<m+1;++y)
cout << A[x][y] << "     ";
cout << "\n";
if(m==n)
{
for(x=1;x<m+1;x++)
for(y=1;y<n+1;y++)
if(x==y)
sum+=A[x][y];
else
if(y==m-(x+1))
sum+=A[x][y];
}

break;
case 3:
// diagonal sum
cout << "Sum of diagonal elements is : " << sum << endl;

break;
case 4:
// quite
return 0;
break;
default:
cout << "Option unknown";
break;
}

[phorce]

Apologies.

I purposly left out main, so, you need to include main..

int main()
{


}

As you had it before, just implement my code. :)

Kinda like this (NOT COMPLETE):

#include <iostream>
using namespace std;

int main()
{
    int choice = 0;
    int A[10][10],m,n,x,y,sum=0;
    //Create a Matrix 
    cout << "Enter number of rows and columns in Matrix A : \n";
    cin>>n>>m;
    cout << "Enter elements of Matrix A : \n";
    for(x=1;x<n+1;++x)
    for(y=1;y<m+1;++y)
    cin>>A[x][y];

        cout << "Please enter an option: \n";
        cout << "\t\t 1) Sum Row\n";
        cout << "\t\t 2) Sum Column\n";
        cout << "\t\t 3) Diagonal Sum\n";
        cout << "\t\t 4) Quit\n";
        cin >> choice;

        switch(choice)
        {
            case 1:
             for(x=1;x<n+1;++x)
             {
                A[x][m+1]=0;
                for(y=1;y<m+1;++y)
                A[x][m+1]=A[x][m+1]+A[x][y];
             }
            break;

            case 2:
             for(y=1;y<m+1;++y)
             {
                A[n+1][y]=0;
                for(x=1;x<n+1;++x)
                A[n+1][y]+=A[x][y];
            }
            cout << "\nMatrix A, Row Sum (Last Column)" << " and Column Sum (Last Row) : \n";
            for(x=1;x<n+1;++x)
            {
               for(y=1;y<m+2;++y)
                cout << A[x][y] << "     ";
                cout << "\n";
            }
            break;

            case 3:
              // diagonal sum
            break;

            case 4:
                // quite
                return 0;
            break;

            default:
              cout << "Option unknown";
            break;

        }

}

Hope this helps.

P.S. Indent your code, it's messy to read.

[diknas]

thanks for the answer :), but when I select the first menu program is exit, how to keep program run and can the calculation sum of each row, each column, and sum of diagonal 1 and diagonal 2, please help me..,

[phorce]

So you want the program to iterate until the user enter's quits?

If this is the case, just add a loop:

Before:
int choice = 0;

   while(choice != 4)
    {

And then close the bracket off at the end of the program:

}