Hi,
I have a code that checks if one specific process is running in the TaskManager with the code below. If not the function will start this process.
The code I use in a Form_Load event when the application starts. (Working code is below)
What I initially wonder is instead of a Form Application, I would only need some kind of file that should run this code. This means that you would double click a file that open/closes very fast while only running this code.
Is this possible to achieve somehow. I am not sure what possibilities there are to do this exactly?
private void Form1_Load(object sender, EventArgs e)
{
bool getInfo = IsProcessOpen("testApp");
if (getInfo == false)
{
//Start the application here
String appLoc = "D:/Programs/testApp.exe";
System.Diagnostics.Process startApplication = new System.Diagnostics.Process();
try
{
startApplication.StartInfo.FileName = appLoc;
startApplication.Start();
}
catch { }
}
}
public bool IsProcessOpen(string name)
{
//here we're going to get a list of all running processes on the computer
foreach (System.Diagnostics.Process clsProcess in System.Diagnostics.Process.GetProcesses())
{
String getName = clsProcess.ProcessName.ToString().ToLower();
if (getName == name)
{
//if the process is found to be running then we return a true
return true;
}
}
//otherwise we return a false
return false;
}
