Python Steganography Help !

[Izio]

Hi there, I need some help to finish that code, In fact, there is one problem in my code : The last line, when i tried to convert a hexadecimal number in int. The problem is, I got variables containing : ff or 00 or C6 etc... And i want to add "0x" at the begining, for that, I added as string, but when i tried to convert in int, this doesn't work, and it said :

----- File "Stegano Real.py", line 138, in <module>
r3.append(int(i))
ValueError: invalid literal for int() with base 10: 'oxff' ----

Here it's my code :

import PIL.Image
from tkinter import *
import os



im1 = PIL.Image.open('header.png') # Ouverture de l'Image à cacher 1
im1.putalpha(0)  # Insertion du canal Alpha (transparance)
px1 = list(im1.getdata()) # Insère dans la liste le RGBA de tt les pixels.



r1 = [] # Création des listes RGBA
g1 = []
b1 = []
a1 = []

for i in px1 :  # Affectation des valeurs aux listes respectives.
    list(i)
    r1.append(i[0])
    g1.append(i[1])
    b1.append(i[2])
    a1.append(i[3])


rhex1 =[]  # Création des liste pour les haxadécimales
ghex1 = []
bhex1 = []
ahex1 = []

for i in r1 : # Hexadécimalage des listes.
    rhex1.append(hex(i))
for i in g1 :
    ghex1.append(hex(i))
for i in b1 :
    bhex1.append(hex(i))
for i in a1 :
    ahex1.append(hex(i))

rhex1fort = []  # Création des listes pour les hexa fort (1er)
ghex1fort = []
bhex1fort = []
ahex1fort = []


for i in rhex1 :            
    rhex1fort.append(i[2])
for i in ghex1 :
    ghex1fort.append(i[2])
for i in bhex1 :
    bhex1fort.append(i[2])
for i in ahex1 :
    ahex1fort.append(i[2])
# -------------------------------------------------------   

im2 = PIL.Image.open('header2.png') # Ouverture de l'Image
im2.putalpha(0)  # Insertion du canal Alpha (transparance)
px2 = list(im2.getdata()) # Insère dans la liste le RGBA de tt les pixels.



r2 = [] # Création des listes RGBA
g2 = []
b2 = []
a2 = []

for i in px2 :  # Affectation des valeurs aux listes respectives.
    list(i)
    r2.append(i[0])
    g2.append(i[1])
    b2.append(i[2])
    a2.append(i[3])


rhex2 =[]  # Création des liste pour les haxadécimales
ghex2 = []
bhex2 = []
ahex2 = []

for i in r2 : # Hexadécimalage des listes.
    rhex2.append(hex(i))
for i in g2 :
    ghex2.append(hex(i))
for i in b2 :
    bhex2.append(hex(i))
for i in a2 :
    ahex2.append(hex(i))

rhex2fort = []  # Création des listes pour les hexa fort (1er)
ghex2fort = []
bhex2fort = []
ahex2fort = []


for i in rhex2 :            # Récupération des bytes forts de la 2eme im
    rhex2fort.append(i[2])
for i in ghex2 :
    ghex2fort.append(i[2])
for i in bhex2 :
    bhex2fort.append(i[2])
for i in ahex2 :
    ahex2fort.append(i[2])


# mettre le bytes fort 2 en bytes faible dans la liste.

rhex3 = []
ghex3 = []
bhex3 = []
ahex3 = []

s=0
for i in rhex2 :
    rhex3.append("ox"+rhex1fort[s]+rhex2fort[s])
    s=s+1
s=0
for i in bhex2 :
    bhex3.append("ox"+bhex1fort[s]+bhex2fort[s])
    s=s+1
s=0
for i in bhex2 :
    bhex3.append("ox"+bhex1fort[s]+bhex2fort[s])
    s=s+1
s=0
for i in bhex2 :
    bhex3.append("ox"+bhex1fort[s]+bhex2fort[s])
    s=s+1

r3 =[]
g3 = []
b3 = []
a3 = []




for i in rhex3 :
    r3.append(int(i))
for i in ghex3 :
    g3.append(int(i))
for i in bhex3 :
    b3.append(int(i))
for i in ahex3 :
    a3.append(int(i))


print(bhex2)

[jacks009]

Check line by line error and check and brif expalain on query or suggestions .

[Izio]

I already do that, else I didn't post here..
But, my real problem is, imagine this code :

a = "0x" + "ff" # So a = "0xff"
# and i want to have a = 0xff 
# Because I want to do int(a)to have 255.

[Gribouillis]

Try int('ff', base=16)

edit:
also have a look at standard modules binascii and array.

[Izio]

I want to kiss you on your mouth ! I love you ! Kingman ! <3 <3 <3