Another List if statment

[Matt Tacular]

I would post this in my other thread, but I marked that as solved so I think less people would look at it. I want to say this:

if list1 is empty:
      do this
elif list1 has any value in it:
      do this

How do I word that in python?

[ghostdog74]

I would post this in my other thread, but I marked that as solved so I think less people would look at it. I want to say this:

if list1 is empty:
      do this
elif list1 has any value in it:
      do this

How do I word that in python?

>>> a = []
>>> if a:
... 	print "not empty"
... 
>>> b = ['a']
>>> if b:
... 	print "not empty"
... 
not empty
>>>

or you can use len()

[jrcagle]

or for the literal match,

if not list:  # condition will be True if 'list' is any of 0, [], "", (), etc. 
   do(this)
else:
   do(that)

[vegaseat]

This might be easier to understand ...

# test if list is empty

list1 = []
list2 = [7]

if len(list1) > 0:
    print "list1 is not empty"
else:
    print "list1 is empty"
    
if len(list2) > 0:
    print "list2 is not empty"
else:
    print "list2 is empty"

"""
output =
list1 is empty
list2 is not empty
"""

[Matt Tacular]

Thanks guys this helped alot.