Could someone please help. I would like to sort a multidimensional array. But to sort it out by one key which appears in all array for example.
total=[[serial,'john'],[[serial,'james']]all the records i have all in arrays they contain a "serial" i would like sort by serial.
I have used
total.sort()this sorted that names but johns serial is the first and i would like to sort by serial not by name. Please help :S
Jump to PostThere are number of ways, but this way I mostly use:
# sorting a list of lists by index def sort_inner(inner): """ inner is each inner list in the list of lists to be sorted (here item at index 1 of each inner list is to be …
There are number of ways, but this way I mostly use:
# sorting a list of lists by index
def sort_inner(inner):
"""
inner is each inner list in the list of lists to be sorted
(here item at index 1 of each inner list is to be sorted)
"""
return inner[1]
serial = 123456
total = [[serial, 'john'], [serial, 'james']]
total.sort(key=sort_inner)
print total # [[123456, 'james'], [123456, 'john']]Could someone please help. I would like to sort a multidimensional array. But to sort it out by one key which appears in all array for example.
total=[[serial,'john'],[[serial,'james']]all the records i have all in arrays they contain a "serial" i would like sort by serial.
I have used
total.sort()this sorted that names but johns serial is the first and i would like to sort by serial not by name. Please help :S
if you have Python 2.4 or above,
>>> import operator
>>> serial = 12345
>>> total=[[serial,'john'],[serial,'james']]
>>> sorted(total, key=operator.itemgetter(1))
[[12345, 'james'], [12345, 'john']]or even
key=lambda x:x[1]Maby an other short method with the help of List Comprehensions: (very fast) [[id,name]for id in range(2)for name in range(3)] Result:
[[0, 0], [0, 1], [0, 2], [0, 3],
[1, 0], [1, 1], [1, 2], [1, 3],
[2, 0], [2, 1], [2, 2], [2, 3]]
ore in this way [[[id]for id in range(2)]for name in range(3)] Result:
[[[0], [1]], [[0], [1]], [[0], [1]]]
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