can someone please elaborate on code below that evaluates to 42!
//$var is an integer = 42
$var = "3 mice" + 39;
sammy1958
0
Newbie Poster
billah_norm
0
Light Poster
can someone please elaborate on code below that evaluates to 42!
//$var is an integer = 42
$var = "3 mice" + 39;
<?php
//$var is an integer = 42
$str ="mice"; // it is declared as a string is assigned
$int =39; // it declared as integer as a integer value is assigned
echo "<b>str =\"3 mice\";</b> //it is declared as a string is assigned<br>";
echo "<b>int =39;</b> // it declared as integer as a integer value is assigned <br>";
echo "Now we can test the types for each variable using <b>gettype()</b>
function<br>";
echo "The <b>gettype()</b> returns the type of the variable passed
into the parameter
as a string<br>";
echo "For example<br>";
$type1=gettype($str);
$type2=gettype($int);
echo "Type of str is <b>$type1</b> <br>";
echo "Type of int is <b>$type2</b><br>";
echo "Now.........<br>";
echo "When <b>str</b> and <b>int</b> are added using a <b>'+'</b>
operator and the result is assigning into <b>var</b>, the php
interprets <b>str as string</b> and <b>int as integer</b><br>
then it tryes to add the integer int with the given string
value if the <b>str</b> contains any number in its own array
at the first postition<br> If there is no number in the
<b>str</b> it consider <b>str</b> as zero (0) and thus it adds
with int<br>It then assigns the <b>var</b> as <b>integer</b><br>";
$var=$str+$int;
echo "<b>var = str + int<br>";
echo "</b>The result will be <b>39<br>";
$type3=gettype($var);
echo "</b>The type of <b>var</b> is:<b>",$type3;
echo "<br><b>YOU CAN TEST FOR THESE....</b><br>";
$test1="no numbers" + 90;
$type4=gettype($test1);
echo "<br>test1=\"no numbers\"+90<br>";
echo "<b>Result=$test1---$type4";
$test2="if numbers goes here 5 then what??or at the end then??5" + 90;
$type5=gettype($test2);
echo "<br>test2=\"if numbers goes here 5 then what??or at the end then??5\"+90<br>";
echo "<b>Result=$test2---$type5</b>";
echo"<br><b>so it did not find numbers at the first position of the string and
left this considering as string";
?>N.B:You can download PHPEdit which can help you to debug PHP coding.
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