Updating multiple rows in mysql...how to add a checkbox!

Question

Benbo1980 0 Newbie Poster

15 Years Ago

Hi there,

I have successfully setup a page using a tutorial (shown http://www.phpeasystep.com/mysql/10.html)

It's all working fine as it stands.

I have now added another column to the database that can either be 1 or 0 and I would like to be able to change it on the update page using a checkbox for each record.

The code I tried was as follows:

<strong>Update multiple rows in mysql</strong><br> 

<?php 
$host="localhost"; // Host name 
$username=""; // Mysql username 
$password=""; // Mysql password 
$db_name="test"; // Database name 
$tbl_name="test_mysql"; // Table name 

// Connect to server and select databse. 
mysql_connect("$host", "$username", "$password")or die("cannot connect"); 
mysql_select_db("$db_name")or die("cannot select DB"); 

$sql="SELECT * FROM $tbl_name"; 
$result=mysql_query($sql); 

// Count table rows 
$count=mysql_num_rows($result); 
?> 
<table width="500" border="0" cellspacing="1" cellpadding="0"> 
<form name="form1" method="post" action=""> 
<tr> 
<td> 
<table width="500" border="0" cellspacing="1" cellpadding="0"> 


<tr> 
<td align="center"><strong>Id</strong></td> 
<td align="center"><strong>Name</strong></td> 
<td align="center"><strong>Lastname</strong></td> 
<td align="center"><strong>Email</strong></td> 
<td align="center"><strong>On / Off</strong></td> 
</tr> 
<?php 
while($rows=mysql_fetch_array($result)){ 
?> 
<tr> 
<td align="center"><? $id[]=$rows['id']; ?><? echo $rows['id']; ?></td> 
<td align="center"><input name="name[]" type="text" id="name" value="<? echo $rows['name']; ?>"></td> 
<td align="center"><input name="lastname[]" type="text" id="lastname" value="<? echo $rows['lastname']; ?>"></td> 
<td align="center"><input name="email[]" type="text" id="email" value="<? echo $rows['email']; ?>"></td> 
<td align="center"><input name="ONOFF[]" type="checkbox" id="ONOFF" value="1" 
<?php if ($rows['ONOFF'] ==1) { echo "checked";} else {} ?> 
></td> 
</tr> 
<?php 
} 
?> 
<tr> 
<td colspan="4" align="center"><input type="submit" name="Submit" value="Submit"></td> 
</tr> 
</table> 
</td> 
</tr> 
</form> 
</table> 
<?php 
// Check if button name "Submit" is active, do this 
if($Submit){ 
for($i=0;$i<$count;$i++){ 
$sql1="UPDATE $tbl_name SET name='$name[$i]', lastname='$lastname[$i]', email='$email[$i]', ONOFF='$ONOFF[$i]' WHERE id='$id[$i]'"; 
$result1=mysql_query($sql1); 
} 
} 

if($result1){ 
header("location:update_multiple.php"); 
} 
mysql_close(); 
?>

What happens is weird - no matter which checkboxes are ticked, the database appears to update the wrong records. For example, if I had checked every other record (4 in total) and clicked submit, the database would have simply changed the top four records, not necessarily the ones I had originally selected.

Any ideas?!

Thanks,

Ben

php

8 Contributors
9 Replies
1K Views
1 Year Discussion Span
Latest Post 14 Years Ago Latest Post by freshmem

All 9 Replies

R0bb0b 344 Posting Shark

15 Years Ago

Try this

<strong>Update multiple rows in mysql</strong><br> 

<?php 
$host="localhost"; // Host name 
$username=""; // Mysql username 
$password=""; // Mysql password 
$db_name="test"; // Database name 
$tbl_name="test_mysql"; // Table name 

// Connect to server and select databse. 
mysql_connect("$host", "$username", "$password")or die("cannot connect"); 
mysql_select_db("$db_name")or die("cannot select DB"); 

$sql="SELECT * FROM $tbl_name"; 
$result=mysql_query($sql); 

// Count table rows 
$count=mysql_num_rows($result); 
?> 
<table width="500" border="0" cellspacing="1" cellpadding="0"> 
<form name="form1" method="post" action="<? echo $_SERVER['REQUEST_URI']; ?>"> 
<tr> 
<td> 
<table width="500" border="0" cellspacing="1" cellpadding="0"> 


<tr> 
<td align="center"><strong>Id</strong></td> 
<td align="center"><strong>Name</strong></td> 
<td align="center"><strong>Lastname</strong></td> 
<td align="center"><strong>Email</strong></td> 
<td align="center"><strong>On / Off</strong></td> 
</tr> 
<?php 
while($rows=mysql_fetch_array($result))
{ 
?> 
<tr> 
<td align="center"><input type="hidden" name="id[]" value="<? echo $rows['id']; ?>" /><? echo $rows['id']; ?></td> 
<td align="center"><input name="name<? echo $rows['id']; ?>" type="text" id="name" value="<? echo $rows['name']; ?>"></td> 
<td align="center"><input name="lastname<? echo $rows['id']; ?>" type="text" id="lastname" value="<? echo $rows['lastname']; ?>"></td> 
<td align="center"><input name="email<? echo $rows['id']; ?>" type="text" id="email" value="<? echo $rows['email']; ?>"></td> 
<td align="center"><input name="ONOFF<? echo $rows['id']; ?>" type="checkbox" id="ONOFF" value="1" 
<?php if ($rows['ONOFF'] ==1) { echo "checked";} else {} ?> 
></td> 
</tr> 
<?php 
} 
?> 
<tr> 
<td colspan="4" align="center"><input type="submit" name="Submit" value="Submit"></td> 
</tr> 
</table> 
</td> 
</tr> 
</form> 
</table> 
<?php 
// Check if button name "Submit" is active, do this 
if($Submit)
{ 
	foreach($_POST['id'] as $id)
	{ 
		$sql1="UPDATE ".$tbl_name." SET name='".$_POST["name".$id]."', lastname='".$_POST["lastname".$id]."', email='".$_POST["email".$id]."', ONOFF='".$_POST["ONOFF".$id]."' WHERE id='".$id."'"; 
		$result1=mysql_query($sql1); 
	} 
} 

if($result1){ 
header("location:update_multiple.php"); 
} 
mysql_close(); 
?>

You were looping through with a counter and using the loopnumber as your id, this will only work if you are absolutely positive that your ids are sequential, looks like you are using register globals I think. I've never used them so I actually find your code confusing.

Reply to this topic

Be a part of the DaniWeb community

We're a friendly, industry-focused community of developers, IT pros, digital marketers, and technology enthusiasts meeting, networking, learning, and sharing knowledge.

Benbo1980 0 Newbie Poster · Answer 1 · 2008-07-17T06:06:11+00:00

Benbo1980 0 Newbie Poster

15 Years Ago

Thankyou very much - that worked a treat!

jinzing 0 Newbie Poster · Answer 2 · 2008-08-15T03:36:17+00:00

i was having the same problem and this solution worked great! thanks :icon_mrgreen:

withremote 0 Newbie Poster · Answer 3 · 2009-02-17T21:38:43+00:00

I'm getting a Warning: Cannot modify header information - headers already sent by from

<form name="form1" method="post" action="<? echo $_SERVER['REQUEST_URI']; ?>">

when the script hits

if($result1){ 
header("location:update_multiple.php"); 
}

Otherwise it works like a charm. Any idea as to how to avoid this error?

withremote 0 Newbie Poster · Answer 4 · 2009-02-18T20:04:12+00:00

I figured it out.

I needed to use ob_start(); at the top of my page, before any of the script runs, then ob_end_flush(); directly after the redirect.

lemonizer 0 Newbie Poster · Answer 5 · 2009-06-25T00:47:53+00:00

Using the code listed above, this is a subset of code I used for Radio buttons instead of checkboxes.

In addition, I was having trouble detecting the Submit button being used, so that section of the code was changed.

if ($row['YesNo']=="Yes")
  {
  echo "<td><INPUT type=\"radio\" name=\"YesNo".$row['ID']."\" value=\"Yes\" CHECKED> Yes <INPUT type=\"radio\" name=\"YesNo".$row['ID']."\" value=\"No\" > No</td>";
  }
	else {
	echo "<td><INPUT type=\"radio\" name=\"YesNo".$row['ID']."\" value=\"Yes\" > Yes <INPUT type=\"radio\" name=\"YesNo".$row['ID']."\" value=\"No\" CHECKED> No</td>";
	}
  echo "</tr>";
  }
echo "</table>";
}
?>
<input type="Submit" name="Submit" value="Submit">
</form>
<?php
Interviewed='".$_POST['YesNo'.$id]."' WHERE ID=".$_POST['id'];
//echo "<p>SQL:".$sql1;

//check if Submit button is active
if (isset($_POST['Submit']))
{
	echo "<p>submit pressed";
	foreach($_POST['id'] as $id)
	{
		$sql1="UPDATE table SET YesNo='".$_POST['YesNo'.$id]."' WHERE ID=".$id;
		$result1=mysql_query($sql1);
		echo "<p>".$sql1;
	}
}

Silvor 0 Newbie Poster · Answer 6 · 2009-09-07T23:12:39+00:00

This is excellent, helped me greatly!

One question - how can I get it to INSERT a row if there is currently no row with that ID?

I want to be able to update all rows that it can update and insert rows which aren't currently there?

Thank you.

Helleshtern 0 Newbie Poster · Answer 7 · 2010-02-04T20:33:05+00:00

I'm trying to use code posted by R0bb0b but it doesn't work for me. After submit nothing happend - status of checked rows don't change. Any help would be appreaciated :(

freshmem 0 Newbie Poster · Answer 8 · 2010-02-08T15:31:36+00:00

i was trying the given code.and i just change the db name ,etc

<?php 
$host="localhost"; // Host name 
$username="root"; // Mysql username 
$password="root"; // Mysql password 
$db_name="test"; // Database name 
$tbl_name="coba"; // Table name 
 
// Connect to server and select databse. 
mysql_connect("$host", "$username", "$password")or die("cannot connect"); 
mysql_select_db("$db_name")or die("cannot select DB"); 
 
$sql="SELECT * FROM $tbl_name"; 
$result=mysql_query($sql); 
 
// Count table rows 
$count=mysql_num_rows($result); 
?> 
<table width="500" border="0" cellspacing="1" cellpadding="0"> 
<form name="form1" method="post" action="<? echo $_SERVER['REQUEST_URI']; ?>"> 
<tr> 
<td> 
<table width="500" border="0" cellspacing="1" cellpadding="0"> 
 
 
<tr> 
<td align="center"><strong>ID</strong></td> 
<td align="center"><strong>Name</strong></td> 
<td align="center"><strong>Address</strong></td> 
<td align="center"><strong>Comment</strong></td> 
<td align="center"><strong>On / Off</strong></td> 
</tr> 
<?php 
while($rows=mysql_fetch_array($result))
{ 
?> 
<tr> 
<td align="center"><input type="hidden" name="ID[]" value="<? echo $rows['ID']; ?>" /><? echo $rows['ID']; ?></td> 
<td align="center"><input name="Name<? echo $rows['ID']; ?>" type="text" id="Name" value="<? echo $rows['Name']; ?>"></td> 
<td align="center"><input name="Address<? echo $rows['ID']; ?>" type="text" id="Address" value="<? echo $rows['Address']; ?>"></td> 
<td align="center"><input name="Comment<? echo $rows['ID']; ?>" type="text" id="Comment" value="<? echo $rows['Comment']; ?>"></td> 
<td align="center"><input name="ONOFF<? echo $rows['id']; ?>" type="checkbox" id="ONOFF" value="1" 
<?php if ($rows['ONOFF'] ==1) { echo "checked";} else {} ?> 
></td> 
</tr> 
<?php 
} 
?> 
<tr> 
<td colspan="4" align="center"><input type="submit" name="Submit" value="Submit"></td> 
</tr> 
</table> 
</td> 
</tr> 
</form> 
</table> 
<?php 
// Check if button name "Submit" is active, do this 
if($Submit)
{ 
	foreach($_POST['ID'] as $id)
	{ 
		$sql1="UPDATE ".$tbl_name." SET name='".$_POST["Name".$id]."', Address='".$_POST["Address".$id]."', Comment='".$_POST["Comment".$id]."', ONOFF='".$_POST["ONOFF".$id]."' WHERE id='".$id."'"; 
		$result1=mysql_query($sql1); 
	} 
} 
 
if($result1){ 
header("location:update_multiple.php"); 
} 
mysql_close(); 
?>

but..when i want to update it always can not be updated..
i think the problem is in this line.IMHO

<tr> 
<td align="center"><input type="hidden" name="ID[]" value="<? echo $rows['ID']; ?>" /><? echo $rows['ID']; ?></td> 
<td align="center"><input name="Name<? echo $rows['ID']; ?>" type="text" id="Name" value="<? echo $rows['Name']; ?>"></td> 
<td align="center"><input name="Address<? echo $rows['ID']; ?>" type="text" id="Address" value="<? echo $rows['Address']; ?>"></td> 
<td align="center"><input name="Comment<? echo $rows['ID']; ?>" type="text" id="Comment" value="<? echo $rows['Comment']; ?>"></td> 
<td align="center"><input name="ONOFF<? echo $rows['id']; ?>" type="checkbox" id="ONOFF" value="1" 
<?php if ($rows['ONOFF'] ==1) { echo "checked";} else {} ?>

for example

Name<? echo $rows['ID']; ?>" type="text" id="Name" value="<? echo $rows['Name']

it will be always return to the inputed value although it has been updated..

anyone can help me?
before i`m really sorry that my english is not so good.. :)

Updating multiple rows in mysql...how to add a checkbox!

Recommended Answers Collapse Answers

All 9 Replies

Recommended Answers