Hey all i have the following code:
<?php include 'config.php'; ?>
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<link href="design.css" rel="stylesheet" type="text/css" />
<meta http-equiv="Content-Type" content="text/html; charset=utf-8" />
<title>Search for <?php echo "$_POST[boat]" ?></title>
</head>
<body>
<?php
$port1 = $_POST[port];
if (isset($port1)) {
echo "This var is set so I will print.";
}
if (strcasecmp("$_POST[port]","Any") == 0);
echo "hi";I get to this code from a form on the previous page which has 3 pull down menus. The user selects a boat, port, and departature port. I want to set the port variable which is in $_POST[port] to a variable. I need to check if the user selected ANY or an actual port, so tried:
if (strcmp($_POST[port], "Any") == 0)
echo "equal";
else
echo "not equal";But for whatever reason i cant set the $_POST[] variable to another PHP variable. When i try this, such as here:
$port1 = $_POST[port];I get this error:
Notice: Use of undefined constant port - assumed 'port' in C:\wamp\www\cruise\script.php on line 12
Anyone got any ideas what im doing wrong?
So i have three user inputs from a user form, and i want to compare the inputs to see if they selected a REAL value or a ANy value (so i can do a search in my database using *). Make sense? A good way to do this would be?