Hello Guys. I need your help, I dont know why the input of my code like this, I have a database which is upload, then categorize by Personal, Animals, And Natures. When I choose Personal i want to show all image in Personal, but my code doing like this, when i choose personal the last image of categorize by personal should only query, if i have 5 image in Personal the last image is shown by 5 times, What is the wrong for my code, please guys, help me to detrmine. tnx.
here my code in index.php
<html>
<head>
<title>Upload Images</title>
</head>
<body>
<table align="Center">
<form action = "get.php" method = "POST" enctype = "multipart/form-data">
<tr>
<td>
Select Category: <select name ="cat">
<option>Personal</option>
<option>Animals</option>
<option>Natures</option>
<select></br>
File:<input type = "file" name = "image"><input type = "submit" value = "Upload" />
</form>
</td>
</tr>
</table>
</body>
</html>
Get.php
<?php
error_reporting (E_ALL^E_NOTICE);
mysql_connect("localhost","root","");
mysql_select_db("images");
if(isset($file)){
echo "Please select an image";
}else{
@$file = $_FILES['image']['tmp_name'];
@$image = addslashes(file_get_contents($_FILES['image']['tmp_name']));
@$imagename = addslashes($_FILES['image']['tmp_name']);
@$image_size = getimagesize($_FILES['image']['tmp_name']);
if($image_size == False){
echo "This is not an image file";
}else{
if($_POST['cat'] == 'Personal'){
mysql_query("INSERT INTO upload (name,image,category) VALUES('$imagename','$image','Personal')");
echo "Saved!";
}
}if($_POST['cat'] == 'Animals'){
mysql_query("INSERT INTO upload (name,image,category) VALUES('$imagename','$image','Animals')");
echo "Saved!";
}
if($_POST['cat'] == 'Natures'){
mysql_query("INSERT INTO upload (name,image,category) VALUES('$imagename','$image','Natures')");
echo "Saved!";
}
}
header("Location: view.php");
?>
view.php
<html>
<head>
<title>View Images</title>
</head>
<body>
<table align="Center">
<form method = "POST" enctype = "multipart/form-data">
<tr>
<td>
Select Category: <select name ="cat">
<option>Personal</option>
<option>Animals</option>
<option>Natures</option>
<select></br>
<input type = "submit" value = "View Photos" />
</form>
</td>
</tr>
</table>
</body>
</html>
<?php
mysql_connect("localhost","root","");
mysql_select_db("images");
if (!isset($_POST['submit']))
{
@$file = $_FILES['image']['tmp_name'];
@$category = $_GET['category'];
$sql = mysql_query ("SELECT * from upload WHERE `category`= '$category'");
$result = $sql;
while ($row = mysql_fetch_array($result)){
$cat = $row['category'];
echo "<img src = getv.php?category=$cat width='250px' height= '250px' />";
}
}
?>
and lastly getv.php
<?php
error_reporting (E_ALL^E_NOTICE);
mysql_connect("localhost","root","");
mysql_select_db("images");
if(isset($_GET['category']))
{
$category = mysql_real_escape_string($_GET['category']);
$query = mysql_query("SELECT image FROM upload WHERE `category` = '$category'");
while($row = mysql_fetch_array($query))
{
$imageData = $row["image"];
$name = $row["name"];
}
header('Content-type:image/jpeg');
echo $imageData;
echo $name;
}
?>
help me guys. thanks in advance.
