Member Avatar for hsmom314

I am trying to display MySQL query results dynamically in a table. Based on the query, the table will have a maximum of 3 columns and 15 rows. I would like to have the results display as follows:

Record 1 Record 16 Record 31
Record 2 Record 17 Record 32

Record 15 Record 30 Record 45

If the query returns less than 16 records, everything should display in the first column; if more than 15 but less than 31 - 2 columns, et al.

I am fairly new to PHP and am trying to learn all I can as I go along. Any books, websites, or online classes you can suggest to increase my knowledge of PHP would be greatly appreciated.

Thanks,

Deb

  • 5 Contributors
  • 5 Replies
  • 874 Views
  • 3 Days Discussion Span
  • Latest Post Latest Post by schizoman

Recommended Answers

All 5 Replies

Member Avatar for sam1

ok i will give you an example:

<html>
<head>
</head>
<body>
 <?php
$host=""; // Host name
$username=""; // Mysql username
$password=""; // Mysql password
$db_name=""; // Database name
$tbl_name=""; // Table name

// Connect to server and select databse.
mysql_connect("$host", "$username", "$password")or die("cannot connect");
mysql_select_db("$db_name")or die("cannot select DB");  
    
 $user_result = "select * from table;";
$qry = mysql_query($user_result) OR die(mysql_error());
$user_array = mysql_fetch_assoc($qry);
echo "<center>";
echo "<table CELLPADDING=10 border =1 >";
echo "<tr>";
echo "<td>".$user_array['field 1']."</td>";
echo "<td>".$user_array['field 2']."</td>";
echo "<td>".$user_array['field 3']."</td>";
echo "</tr>";
echo "</table>";
    }
mysql_close();
?>

</body>
</html>

hope that helps you

Member Avatar for hsmom314

Thank you for your suggestion. However, I don't think I explained what I'm trying to do well enough. I am trying to display one field from my database in this table. The results from the one field should display in a table vertically (max. 15 rows) then start a new column. I've written some code (using a while loop and count function) that will display it horizontally but everything that I try to get it to display vertically ends up duplicating the same record.

Member Avatar for mostafadotnet

try using the SQL limit instruction.for example:

SELECT * FROM 'users' LIMIT 0 10;
SELECT * FROM 'users' LIMIT 10 10;

the first number tell you the index in which the SQL DB needs to start from and the second number tell you the number of rows to be selected.
I think you can easily figure it out.
Also, try using MySQL manual if you use MySQL as your DBMS.

Good luck.

Member Avatar for Ezzaral

You will of course have to implement a paging mechanism if your results exceed rows*columns and you will need to get all of the items into a single array before you generate the <tr> and <td> elements. The following example code shows how you can generate the table you want

<?php
$data = array("a","b","c","d","e","f","g","h","i","j");
$rows = 4;
$itemCount=count($data);
echo "<table>";
for ($row=0; $row < $rows; $row++){
    echo "<tr>";
    for ($itemIndex=$row; $itemIndex < $itemCount; $itemIndex+=$rows){
        echo "<td>".$data[$itemIndex]."</td>";
    } 
}
echo "</table>";
?>
Member Avatar for schizoman

Here's a quick and dirty way to do it with nested "for" loops:

$strQS="select [I]field[/I] from [I]table[/I] order by [I]index[/I]";
$refItems=mysql_query($strQS) or die (mysql_error());
$cols=ceil(mysql_num_rows($refItems)/15);
$tableData=array();
for($x=0;$x<$cols;$x++)
{
	for($y=0;$y<15;$y++)
	{
		$tableData[$y][$x]=@mysql_fetch_assoc($refItems);
	}
}
echo <<<TABLESTART
<table>
<tr>
<th colspan={$cols}>
Your Header Here
</th>
</tr>
TABLESTART;
for($x=0;$x<15;$x++)
{
	echo "<tr>\n";
	for($y=0;$y<$cols;$y++)
	{
		echo "<td>".$tableData[$x][$y][[I]field[/I]]."</td>\n";
	}
	echo "</tr>\n";
}
echo "</table>"
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