The foll code gives o/p as
2310103
28
Now my doubt is why here 10 is printed two times although i m passing t=6 for the d parameter??
#include <stdio.h>
#include <string.h>
int f(int a, int b, int c,int d,int e)
{
printf("%d%d%d%d%d \n",a,b,c,d,e);
return a+b+c+d+e;
}
main()
{
int t;
printf("%d",f(2,(1,(2,(3))),t=10,t=6,3),6);
}
Jump to PostYou are modifying "t" more than once between two sequence points which results in undefined behaviour.
You are modifying "t" more than once between two sequence points which results in undefined behaviour.
Your printf() line of code is a great example of programmers being oh-so clever, while ignoring the virtue of clarity in their code.
If you had written that line of code for me, as your employer, I would give you one warning - and on the next occassion, FIRE YOU, immediately.
Programs are not gilded showcases for your mental gymnastics of code. When a program needs to be modified, de-bugged, or worked on by someone else, the value of being clear, rather than unnecessarily complex, will immediately become apparent.
Programs are not gilded showcases for your mental gymnastics of code. When a program needs to be modified, de-bugged, or worked on by someone else, the value of being clear, rather than unnecessarily complex, will immediately become apparent.
Thank you sir for your advice...actually i am a beginner in c..So i was studing some questions regarding the language when i came across this question..I am also familiar with the fact that such codes are never ever used in practical scenarios....Thanks again for your valuable advice..
printf("%d", expr);
printf("UINT:\t%u\tSYMBOL:%s\r\n", expr1, expr2);
// return type of expr, when evaluated, must match symbolic type given to printf ("%u, %s")
We're a friendly, industry-focused community of developers, IT pros, digital marketers, and technology enthusiasts meeting, networking, learning, and sharing knowledge.