I was wondering what DIM means in psuedocode? I ran across this in my research and I can understand everything except for the DIM and it would help a lot if someone else could let me know what this means. I am working on the simple array process and having trouble. Here it is:

Process
1. Display "Salary Average" as program title
2. Prompt user for employee names
3. Prompt user for employee salary
4. Convert average salary
5. Count salaries above average salary
6. Count salaries below average salary
7. Post final results

Input
EmpName (string:EmpName)
EmpSalary (integer:EmpSalary)

Design
Main Module
Call EmpName Module
Select Case
Case Done = No
DIM Employee Name as EmpName
If EmpName is "" Then
Else
Call EmpSalary Module
If EmpSalary < 0 Then
Case Done = Yes
Call Average Salary Module
Call Salaries Above Module
Call Salaries Below Module
Display "Thank You!!!"
End Main Module

EmpName Module
Input Employee Name
End EmpName Module

EmpSalary Module
Input EmpSalary
End EmpSalary Module

Average Salary Module
Sum EmpSalary
DIM EmpName = 1
Count EmpName
Average Salary = Sum EmpSalary/Sum EmpName
End Average Salary Module

Salaries Above Module
If Salary > Average Salary Then Count
End Salaries Above Module

Salaries Below Module
If Salary < Average Salary Then Count
End Salaries Below Module

## Featured Replies in this Discussion

• DIM is the keyword used in Visual Basic to declare a variable. VB: Dim varname As Object C#: object varname;
• Actually, for this pseudo code (pseudo code is NOT standardized), I think it is the dimension of an array. IE, the C code for ... would likely be ... Since I don't have your professor's definition to be sure, this would be my best guess.
Post Contains: Code

DIM is the keyword used in Visual Basic to declare a variable.

VB: Dim varname As Object
C#: object varname;

ok

Actually, for this pseudo code (pseudo code is NOT standardized), I think it is the dimension of an array. IE, the C code for `DIM EmpName = 1` would likely be `const char* EmpName[1];`

Since I don't have your professor's definition to be sure, this would be my best guess.