Radix Sort Efficency Help?

Question

butler273 0 Newbie Poster

12 Years Ago

So, I'm back once again. This week I'm having issues with efficiency in a Radix Sort Algorithm. From what I understand this is the foundation of this algorithm.
What operations might be costing me? For the basics I suppose I do understand push_ back being costly having to copy the entire array.

My code:

for(int i=0; i<10; i++){
// goes through from least to most significant
    for(int j=0; j<V.size(); j++){
      temp=((V[j]/PowValue) % 10);//finds which bucket the value should be placed under
      Buckets[temp].push_back(V[j]); //places value into correct bucket
    }
//Places values from buckets back into the original vector array
    for(int k=0; k<Buckets.size(); k++){
      for(int l=0; l<Buckets[k].size(); l++){
        V[PosCount]=Buckets[k][l];
        PosCount++;
      }
      Buckets[k].clear();
    }
    PosCount=0;
    PowValue=PowValue*10;
  }

Once again, any help, suggestion, etc. would be much appreciated.

c++

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butler273 0 Newbie Poster · Answer 1 · 2012-03-19T04:53:52+00:00

So, I'm back once again. This week I'm having issues with efficiency in a Radix Sort Algorithm. From what I understand this is the foundation of this algorithm.
What operations might be costing me? For the basics I suppose I do understand push_ back being costly having to copy the entire array.
My code:
for(int i=0; i<10; i++){
// goes through from least to most significant
    for(int j=0; j<V.size(); j++){
      temp=((V[j]/PowValue) % 10);//finds which bucket the value should be placed under
      Buckets[temp].push_back(V[j]); //places value into correct bucket
    }
//Places values from buckets back into the original vector array
    for(int k=0; k<Buckets.size(); k++){
      for(int l=0; l<Buckets[k].size(); l++){
        V[PosCount]=Buckets[k][l];
        PosCount++;
      }
      Buckets[k].clear();
    }
    PosCount=0;
    PowValue=PowValue*10;
  }
Once again, any help, suggestion, etc. would be much appreciated.

Nevermind this