I've been trying for a while and can't figure it out
http://pastebin.com/4PZj2c9s

## Featured Replies in this Discussion

• Check if the board is full, meaning that all cells are occupied and not empty Then make sure there aren't any winning patterns for 'x' -- use your checkAll('x') Then make sure there aren't any winning patterns for 'o' -- use your checkAll('o') If all the above passed then it is a tie
• It should be something like so, in psuedo code: ...
Post Contains: Code

• Check if the board is full, meaning that all cells are occupied and not empty
• Then make sure there aren't any winning patterns for 'x' -- use your checkAll('x')
• Then make sure there aren't any winning patterns for 'o' -- use your checkAll('o')
• If all the above passed then it is a tie

I'm having trouble figuring out how to check if all squares are full, could I get some more help with that?

It should be something like so, in psuedo code:

``````bool isFull(board){
bool isFull = true;
for i = 0 to board.length   # 0 <= i <= 8
if board[i] != 'x' && board[i] != 'o'
isFull = false;
break;

return isFull;
}
``````

i am getting an invalid syntax error for that first line
sorry i havent learned bool yet :/
i also cant find anything about 'bool' after googling it

ok so i kind of understand bool now but still have no idea whats wrong
updated code: (line 36)
http://pastebin.com/9na85n80

back to square one, any other help would be very appreciated, all i need now is how to check if the board is full

``````def is_full(board):
return all(p in tuple('xo') for p in board)
``````

or

``````def is_full(board):
return not ''.join(str(p) for p in board).strip('xo')
``````
You