1,694 Topics
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I am using jquery.filedrop.js to create a HTML5 drop box for users. Currently I have it working about 2/3s the way I want it to. The company does yearly conferences, and I have a file path 'file/path/to/conferencefiles' where I save media (docs, images, vids, etc) based on the YEAR of …
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Hi, Am trying to get some data from DB , here am checking whether username is registered or not , if he register am getting some data related to that user and displaying on window . I want function to wait for untill user finish typing his username , then … 
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Greetings! I took some code from this [site](http://osvaldas.info/elegant-css-and-jquery-tooltip-responsive-mobile-friendly). It works great in EVERY browser but IE7 where the arrow of the tooltip is missing. I know that there are issues with IE7 not supporting :after in CSS. I've tried adding this code: <!--[if lt IE 8]> <script src="http://ie7-js.googlecode.com/svn/version/2.1(beta4)/IE8.js"></script> <![endif]--> But …
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I am having the form <html> <head> <script src="//ajax.googleapis.com/ajax/libs/jquery/1.8.3/jquery.min.js"></script> <script src="form.js"></script> </head> <? mysql_connect('localhost','root',''); mysql_select_db('test'); $query="SELECT * FROM user"; $result=mysql_query($query); ?> <div id="contact_form"> <form name="contact" action=""> <fieldset> <label for="txn_unit" id="txn_unit">Txn Unit</label> <SELECT name="name" id="name"> <OPTION value="">SELECT</OPTION> <? while($row=mysql_fetch_assoc($result)) { ?> <OPTION value="<? echo $row['id']; ?>"><? echo $row['first_name']; ?></OPTION> <? } …
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I have a project where my code will have to coexist with code in web pages designed elsewhere. My code will use jQuery, and so there may be an issue if the parent page already runs jQuery (and maybe jQuery plugins). I would have thought the correct thing to do …
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Hi, im am having a smal issue whereby i am using a highchart api based on jquery to display stats. but the stats are stored statically in a table in html and throught which the graph are shown. Nnow i implemented php/mysql to get the data directly from db. So …
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My site is www.jeremyspence.net78.net. As you scroll down I want to make the main menu dissapear(the one menu you see now) and another smaller menu (kinda like the apple menu from apple.com) appear on the top that is fixed, I was thinking about making a sticky menu, but I want … 
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Hello there, I've created an upload system with PHP and its working fine but I need to improve it by using jquery, I need only a progress bar for uploading operation I don't have **apc** installed on server and can't tell the server owner to install it for me is …
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Hi , I have table created by Json : function show(json) { var content = '<tbody>'; var counter; for(counter = 0; counter < json.length; counter++) { content += '<tr><td>' + json[counter]['id'] + '</td>' + '<td>' + json[counter]['time'] + '<td>' + json[counter]['fullname'] + '</td>' + '<td>' + json[counter]['message'] +'</td>' +'<td>' + …
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I had a jquery-based code that messed up the slider on my page @ http://formidablehoops.blogspot.com Is there a way to have those two co-exist, or is there a way to toggle my calendar at the bottom with javascript instead? I've removed the code for now, but I think it's a …
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**<iframe width="608" frameborder="0" id="mainframe" name="mainframe" onload="$(this).height($(this).contents().height());" src="mindex/forratt.php" scrolling="no" /></iframe>** So I have written this code to automatically adjust the iframe to its content and it works fine. The thing is that when I access a page with a lower height, the height from the previous page stays put. I want …
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I'm trying to see how to load jQuery at run time. I can't understand why the following code doesn't work (probably me making a silly error) <!DOCTYPE HTML> <html lang="en"> <head> <meta charset="utf-8"> <script> var script = document.createElement('script'); script.src = 'https://ajax.googleapis.com/ajax/libs/jquery/1.8.0/jquery.min.js'; document.getElementsByTagName('head')[0].appendChild(script); </script> </head> <body> <a href="#" id="main">click me</a> <script> …
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Alright. I am a beginner and I am unable to find a solution to this problem. I am developing this quizzing application. I have built the part that allows you to create and manage questions classified by difficulty and tags. But Im not able to think of a proper quiz … 
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I want to change an image in another place on my site when I click on the page title. I have tried doing different codes five ways to Sunday and cannot figure it out. Can someone help? Here's my code: <!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01//EN" "http://www.w3.org/TR/html4/strict.dtd"> <html> <head> <meta … 
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I want to split the image equaly by vertically. This images should be in slideshow. Then give the link to that two parts. Left side link is for moving to previous slideshow and right side link is for moving to next slide. Anyone can help? Please!
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Hi all. I am a beginner in Zend and I am wondering if there is any good book or tutorial for developing applications with Zend Framework, using json for data encoding and decoding and how to use jquery with Zend. Thanks.
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I have a slider that load all of my content at once. Into a div. Like so: external page.php $get_users = mysql_query("SELECT * FROM user WHERE id!='$user_id'"); while ($rows = mysql_fetch_assoc($get_users)) { $id = $rows['id']; $firstname = $rows['firstname']; $display_info .= ' <div class="f_outer" id="' . $id . '"> <div class="f_name … 
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Hi guys... i want to delete data from datagrid in mysql...i have also done update query using same datagrid... but i m not able to delete data... my code is <script type="text/javascript"> $(document).ready(function () { // prepare the data var data = {}; var theme = 'classic'; var source = … 
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i have so many categories and each category have so many items. like a food website. ok now i want to use fancy box. when burger category was click . i want to show different fancy box. and when kebabas category was clicked i want to show another fancybox.. The …
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I am having the most annoying situation. Ok, here goes. I am using a javascript based sliding menu for a mobile app. The "slider" works just like Facebook mobile, where u can click the button to show the menu on the left and click it again to close the menu. … |
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Hello guys, i've being searching for how is it possible to get value of a form element i.e selection tag that was injected by jquery be access on submitting the form. All the form element value where posted except for the selection element that was injected with jquery. how can …
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I am a beginner at Jquery, and am trying to implement easy slider onto a website. I have the slider on the page, but nowhere near the correct location. I think the issue is stemming from the fact there are two CSS files, and the screen.css file (which is tied …
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I have a file with the name foo.htm inside a folder abc. I am invoking the below script from another html page known as query.html in the folder abc. $.ajax({ url: '/foo.htm', method: 'GET', complete: function(a,b){ alert('complete-2'); }, success: function(a){ alert('good-2'); }, error: function(a,b){ alert('problem-2'); }, }); However, I am … 
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On index.php, change the functionality of your update button's click event so that: 1. when the user clicks on update button it "changes comment text to a textbox with the same value". This requires you to write a javascript to first hide your <div id="comment_1">the first comment</div> and then dynamically …
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I have a question of dynamic elements in php loaded through mysql. The PHP code is as follow <?php $query = "SELECT * FROM `fee_table` WHERE fee_class_id = 6 "; $result = mysql_query($query) or die(mysql_error()); // Print out the contents of the entry echo "<table width='400'>"; echo "<th width='10' scope='col'>Qty</th>"; …
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Hello everyone. I am building an Android app using Dreamweaver with the Jquery Framework and I am having trouble viewing source code of a given URL using javascript. I want the user to be able to type a url into a textfield, and then hit a button and have it …
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i am facing another issue. i want to delete row via ajax and fadeout. i have write below code. this is successfully deleted the row but do not fadeout. var parent = $(this).parent().parent(); $.ajax({ type: "POST", url: "delete_order.php", data: "id="+id, success: function(){ row.find("td").fadeOut(1000, function(){ $(this).parent().remove();}); } }); return false;
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Hi there, am I doing something wrong with the if-statement? it either doesn't evaluate the conditions I've got in there or throw an error. $('button').click(function(){ var button = $($(this)).text(); console.log(button); // this logs the value of button as night or day depending on the button I click if(button == 'day'){ …
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I got a great response from this site. now my final thing is show gif loading image while getting data in Ajax.. my code is : function vote(id) { var result = new Array(); document.getElementById('sub-cat').innerHTML = ajax_image; result = $.ajax({ type: "POST", url: "ajax.php", data: "id="+id, async: false }).responseText.split("^"); document.getElementById('sub-cat').innerHTML …
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Hi everybody. I'm building an site that will load a bunch of overlays into Google Maps. The overlays are static and already in JSON format to be loaded with AJAX. This all works fine, ajax request, json parse, adding overlay. But the json files are quite big, the largest has …
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