#include #include int main() { int n,nstart,nstop,nstep,i,j,zNumber; ` printf("Please enter a value of a positive integer nstart: "); scanf("%d",&nstart); printf("Please enter a value of a positive integer nstop: "); scanf("%d",&nstop); printf("Please enter a value of a positive integer nstep: "); scanf("%d",&nstep); printf("Number\t\tzNumber\n"); printf("------\t\t-------\n"); n=nstart; zNumber= double pow(double_n,double_i); while(i<=nstop){ zNumber = 1; i=1; while(i<=n){ zNumber +=i; i++; } printf("%d\t\t%d\n",n,zNumber); n += nstep; } return 0; } +0 Hi Everyone, For a couple weeks, I have been developing a pi approximation program and making little upgrades. Right now, the program asks for an input of iterations and then prints out the approximation. Now, I want to have every iteration printed out into an excel file with an approximation accurate to .000001 [50,000 iterations] However, I realized that the current setup of my program does not work well, so I think some rework is in order. So my goal is to eliminate the input process; and instead, base the iterations on accuracy, not input. That is what I would … +0 I'm trying to create a program that computes the values of cos using the Taylor Series as long as the absolute value of a term is greater than 0.0001 and prints the number of terms used in the series approximation. My code is the following and as of right now I am getting the wrong result. Please help me fix it! I've spent hours trying to figure it out and don't know what to do. Enter the angle in radians: 3.14 There were 8 numbers of terms used in the series approximation. The calculated cosine of 3.14 is 0.00499852 The … +0 //A1 = 1 //An = An-1 +sqrt(An-1) for n > 1. //i need to find An of the series according to the estimation An=(n^2)/4 //how do i write a member of the series, let's say "An" in the code and to apply "n>1" in the code? +0 How to find this series without using power function in c 1+x/1!+x2/2!+x3/3!+x4/4! please help me out i'm unable to solve these type of questions +0 How to find this series without using power function in c 1+x/1!+x2/2!+x3/3!+x4/4! please help me out i'm unable to solve these type of questions -1 Pls help me on this. I really dont have an idea of solving this. Here's the question .. 1. Write a c++ program that generates the following series: 0 -1 4 -9 16 -25 36 -49 64 -81 100 and also this one 2. write a program that generates the fibonacci series: 1 1 2 3 5 8 13 up to 50th term. I was shocked when i saw this :-O It is not yet taking up. But pls. Help me. Thanks alot.. - Nell +0 /*PROGRAM TO PRINT SUM OF THE FOLLOWING SERIES - X + X*X/2! + X*X*X/3! + X*X*X*X/4!....n terms. I'm not getting the correct output. eg-for n=3 and x=2; compiler's ans = 4.66 correct ans = 5.3. HELP ME OUT...*/ [CODE]#include #include #include void main () { clrscr(); float x,sum=0; int n,fact=1,j,k; cout<<"\nEnter For n"; cin>>n; cout<<"\nEnter For X"; cin>>x; for(int i=1;i<=n;++i) { j=i; k=i; { while(j) { fact=fact*j; --j; } } sum+=pow(x,k)/fact; } cout<<"The Sum Of Series Is:"< #include using namespace std; double fac(int n) { double f=n; while (--n)f*=n; return f; } int main() { double long x; cout << "Enter Angle in Radians: " << endl; cin >> x; double cos(0.0); … +0 How to get the following output using c? ---1 --12 -345 6789 Please guide me with the code. It can be a blank space instead of '-'. +0

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