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Re: Word Association Game 17 Years Ago by yogi_bear_2k2 singer --> Kylie Minogue...? Re: 3 word story 17 Years Ago by happygeek singer of rubbish Re: Word Association Game 16 Years Ago by paramasivan singer--->K.J.Yesudas Re: Who is your favourite female singer? 12 Years Ago by sergent [QUOTE]and hmmmmm... Pussy Cat Dolls hehe[/QUOTE] Love them too ;) But my favorite female singer is Michael Jackson Re: Who is your favourite female singer? 12 Years Ago by jingda You guys are funny. I said favourite female singer means you can only choose one.Ayagi choose 5 and Michael Jackson is not a female. problem while uploading songs 9 Years Ago by hriti … $song_url =$record['song_url']; $thumbnail =$record['thumbnail']; $singer =$record['singer']; $lyrics =$record['lyrics']; $video_url =$record['video_url'];…='".mysql_real_escape_string($song_title)."', singer='".$singer."', video_url='".mysql_real_escape_string($video_url… How to increment a variable in XSLT 14 Years Ago by himit …code] Want output as- [code] <root> <singer> singer no. [COLOR="Red"]1 [/COLOR] [B]<!--…title>Empire Burlesque</title> </singer> <singer> singer no. 2 <!--not able to get this…xsl:for-each select="cd"> <singer> singer no. <xsl:value-of select="$num"… how to deserlized following json in asp.net(c#) 12 Years Ago by Aties …quot;: "Subir (Amitabh Bachchan) is a professional singer whose career is soaring. He does not plan to marry…;synopsis": "Subir (Amitabh Bachchan) is a professional singer whose career is soaring. He does not plan to marry…": "Subir (Amitabh Bachchan) is a professional singer whose career is soaring. He does not plan to marry… Re: call the value from my source XML to the element in my result XML 14 Years Ago by himit …lt;title>Empire Burlesque</title> </singer> <singer ab:name=”Bonnie Tyler”/> <title>… try it without ":" it works. <singer> <xsl:attribute name="ab:name"&…quot;title"/> </title> </singer> <singer> <xsl:attribute name="abname"&… Re: How to increment a variable in XSLT 14 Years Ago by himit …;xsl:for-each select="cd"> <singer> singer no. <xsl:value-of select="position()"/>…; <xsl:copy-of select="title"/> </singer> </xsl:for-each> </xsl:template>… Re: How to increment a variable in XSLT 14 Years Ago by fpmurphy …> <xsl:template match="cd"> <singer> singer no. <xsl:number /> <xsl:copy-of… select="./title"/> </singer> </xsl:template> </xsl:stylesheet> [/code… XML to XML transformation 15 Years Ago by rat1973 …: [code] <root> <singer>Bob Dylan</singer> <singer>Bonnie Tyler</singer> </root> [/code…="catalog/cd"> <xsl:element name="singer"> <xsl:value-of select="artist"… Music quiz 15 Years Ago by The Dude …90-s-Albums-can-you-match-it-the-the-singer-band-P-1174539822.shtml[/url] [url]http://…90-s-Albums-can-you-match-it-the-the-singer-band-P-1174540359.shtml[/url] [url]http://…90-s-Albums-can-you-match-it-the-the-singer-band-P-1174540842.shtml[/url] [url]http://…90-s-Albums-can-you-match-it-the-the-singer-band-P-1174541394.shtml[/url] I only got… Field List Input Problem 14 Years Ago by dwdata …;>Leader</option> <option value="Singer">Singer</option> <option value="Piano"…;>Leader</option> <option value="Singer">Singer</option> <option value="Piano"… Re: Field List Input Problem 14 Years Ago by dwdata …] $selected = explode(',',$Instruments); //instrument data from database $instruments = array('Leader','Singer','Piano'); $options = ''; foreach( $instruments as $inst ) { $sel = ''; if ( in_array(…;Leader</option> //<option value="Singer">Singer</option> //<option value="Piano&… Sorting a Query by a Given List 14 Years Ago by dwdata … need is by Priority. I need it like this: Leader Singer Piano Synth A-Guitar E-Guitar Bass Drums Perc Sax… list like this: Smith, Bill - Leader Hanster, Tom- Singer Raller, Jen - Singer Tombs, Sara - Singer Joel, Billy - Piano Taylor, James - A-Guitar Carlton… call the value from my source XML to the element in my result XML 14 Years Ago by himit …catalog> Want output as- <root> <singer name=”Bob Dylan”> <!--this name is the value…lt;title>Empire Burlesque</title> </singer> <singer name=”Bonnie Tyler”/> <title>Hide …your heart</title> </singer> </root> I don’t even know… User input box not displaying in Jframe context 13 Years Ago by themarval … of this CD //----------------------------------------------------------------- public void setArtist(String singer) { artist = singer; } //----------------------------------------------------------------- // Sets the price of this CD //----------------------------------------------------------------- public… Accessing Database from another form 11 Years Ago by eongchin ….Rows If row.Item("LastName").Equals("Singer") Then MessageBox.Show(" name = "…quot;) If row.Item("LastName").Equals("Singer") Then MessageBox.Show(" name = "…the whole database to find lastname = singer, how am i able to obtain the firstname… chown not working 8 Years Ago by lewashby … 39 Jun 27 22:17 The Wedding Singer.mkv -> ../Movies-Secure/The Wedding Singer.mkv lrwxrwxrwx 1 root root 35 Jun… 39 Jun 27 22:17 The Wedding Singer.mkv -> ../Movies-Secure/The Wedding Singer.mkv lrwxrwxrwx 1 root root 35 Jun… Re: XML to XML transformation 5 Years Ago by Krishna_30 …;xsl:for-each select="catalog/cd"> <singer><xsl:value-of select = "artist" />…;</singer> </xsl:for-each> </root> <… Re: XML to XML transformation 15 Years Ago by fpmurphy …;catalog/cd/artist"> <xsl:element name="singer" > <xsl:value-of select="."/>… Re: Field List Input Problem 14 Years Ago by somedude3488 …;>Leader</option> <option value="Singer">Singer</option> <option value="Piano"… Re: call the value from my source XML to the element in my result XML 14 Years Ago by me655321 I'm not an expert in XSLT but I think you can do that with something like this:[CODE]<singer> <xsl:attribute name="name"> <xsl:value-of select="artist"/> </xsl:attribute> <title><xsl:value-of select="title"/></title> </singer> [/CODE] Looping Data 10 Years Ago by vividiah …= "INSERT INTO iMUSIC " & _ "(ID_MUSIC, TITLE, SINGER, FID_M_CATEGORY, FILE_NAME, SOURCE, PATH, ACTIVE, VOL , ANALOG, DATE_ADDED)" &… End If Do While Not rsmusik.EOF Text2.Text = rsmusik!singer Text3.Text = rsmusik!Title CB_kategori.Text = rsmusik!id_kategori rsmusik.MoveNext… Re: Looping Data 10 Years Ago by aktharshaik …"INSERT INTO iMUSIC " & _ "(ID_MUSIC, TITLE, SINGER, FID_M_CATEGORY, FILE_NAME, SOURCE, PATH, ACTIVE, VOL , ANALOG, DATE_ADDED)"… 'at the end of the loop Text2.Text = rsmusik!singer Text3.Text = rsmusik!Title CB_kategori.Text = rsmusik!id_kategori … Re: Field List Input Problem 14 Years Ago by somedude3488 …] $selected = explode(',',$Instruments); //instrument data from database $instruments = array('Leader','Singer','Piano'); $options = ''; foreach( $instruments as $inst ) { $sel = ''; if ( in_array( $inst… Re: Field List Input Problem 14 Years Ago by dwdata …] $selected = explode(',',$Instruments); //instrument data from database $instruments = array('Leader','Singer','Piano'); $options = ''; foreach( $instruments as $inst ) { $sel = ''; if ( in_array( $inst… Re: Sorting a Query by a Given List 14 Years Ago by cwarn23 … need is by Priority. I need it like this: Leader Singer Piano Synth A-Guitar E-Guitar ...[/QUOTE] [QUOTE]Won't… Final GUI JFrame problem with actionlistner method 17 Years Ago by nabil1983 … ("X-Men ","Hugh Jackman ","Bryan Singer ","Superhero adventures ","120 ","Yes…;The Usual Suspects ","Kevin Spacey ","Bryan Singer ","Criminals head for a big payday ","…