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Member Avatar for da(code)da

Ok I have a promblem. Im getting a unidentified variable error from **$found:** Whats wrong here? while($row = mysql_fetch_array($result)) { **$found** = true; echo "Character/Alias: " . $row["CharName"] . "<br>Created: " . $row["CharBorn"] . "<br>Game: "; if ($row["CharGame"] == '0') { echo "None"; } else { echo "In-Game"; } } …

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Member Avatar for collinskawere

hello! am trying to do a simple search engine, but whenever the user types a search term, the script returns the error: unidentified variable: name. name was the input name in the html code. ie (input name="name"). thanks. <?php $db = mysql_connect("localhost", "root", ""); mysql_select_db("room_p7", $db); $query = "select name, …

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The End.