With a growth rate of 30%, it'll be at 130% after each year. Since that compounds, you'll just have a simple formula of:
[tex]pop = 2000(1.3^x)[/tex]
This assumes the compounding happens at one instant per year, rather than calculating continuously.
Plug that in, and you'll get 5712
Infarction
Posting Virtuoso
1,580 posts since May 2006
Reputation Points: 683
Solved Threads: 53
pop = 2000
Loop 4 times
pop = pop + (pop * 30%)
end loop
WaltP
Posting Sage w/ dash of thyme
10,492 posts since May 2006
Reputation Points: 3,348
Solved Threads: 943
These are all the same basic equation.
Calculate the first value from the original value.
Use that new value and calculate again.
Repeat the specified number of times.
WaltP
Posting Sage w/ dash of thyme
10,492 posts since May 2006
Reputation Points: 3,348
Solved Threads: 943
These are all the same basic equation.
Calculate the first value from the original value.
Use that new value and calculate again.
Repeat the specified number of times.
lol yea.. they seem like homework problems to me...
joshSCH
Industrious Poster
4,864 posts since Jul 2005
Reputation Points: 1,315
Solved Threads: 10
Kirk: "There must be thousands of them, tens of thousands..."
Spock: "One million, seven hundred seventy one thousand, five hundred and sixty one. That's assuming they got in here six days ago, and a litter of ten each day."
It's the same formula, in this case 11 ^ 6.
MidiMagic
Nearly a Senior Poster
3,319 posts since Jan 2007
Reputation Points: 730
Solved Threads: 182