I need help understanding the following
Machine A runs a program in 10s at 400MHZ
We want machineB to run the same program in 6s.
Machine B will require 1.2 * clock cycle than machine A.
Why is it 1.2? I can't figure it out.
london-G
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Jump to PostI get a factor of 1.67 . If you need to explain that 1.2 is the correct factor, then you have to say that something else is important. Maybe I/O on the new machine is faster or the new machine has faster/larger CPU-side cache or ...
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london-G
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Anyone?
griswolf
304
Veteran Poster
I get a factor of 1.67 . If you need to explain that 1.2 is the correct factor, then you have to say that something else is important. Maybe I/O on the new machine is faster or the new machine has faster/larger CPU-side cache or ...
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