How to get the invoked command and parameters as one string instead of a list of argv-s (especially gcc under Linux)?
skabaw
0
Newbie Poster
Recommended Answers
Jump to PostBuild it manually:
#include <iostream> #include <string> int main ( int argc, char *argv[] ) { std::string args; for ( int i = 0; i < argc; i++ ) { args += argv[i]; if ( i != argc - 1 ) args += ' '; } std::cout<< …
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Narue
5,707
Bad Cop
Team Colleague
Build it manually:
#include <iostream>
#include <string>
int main ( int argc, char *argv[] )
{
std::string args;
for ( int i = 0; i < argc; i++ ) {
args += argv[i];
if ( i != argc - 1 )
args += ' ';
}
std::cout<< args <<'\n';
}
skabaw
0
Newbie Poster
Yes, that's clear. I just thought there is a built-in function or environment variable.
Narue
5,707
Bad Cop
Team Colleague
>I just thought there is a built-in function or environment variable.
Built-in solutions usually arise from a very common problem or a difficult to implement problem. Yours is neither. You might get lucky, but more often than not you'll end up needing a third party or custom solution for uncommon and trivial to implement problems.
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