leep year

[system analysis]

please help me to Design and implement an application that reads an integer value representing a year from the user. The purpose of the program is to determine if the year is a leap year (and therefore has 29 days in February) in the Gregorian calender. A year is a leap year if it is divisible by 4, unless it is also divisible by 100 but not by 400.
For example, the year 2003 is not a leap year, but 2004 is. The year 1900 is not a leap year because it is divisible by 100 but not by 400. The year 2000 is a leap year because it is divisible by 100 and also divisible by 400. Produce an error message for any input value less than 1582 (the year the Gregorian calender was adopted).

The application should display the result to the console window, as below

Enter a year: 2000
The year 2000 is a leap year.

[masijade]

Okay. What do you have so far?

[javaAddict]

A year is a leap year if it is divisible by 4, unless it is also divisible by 100 but not by 400.

There is your if statement.
Use this '%' operator to determine if a number is divisible by another number.
It returns what is left by the division. If it returns 0 then it is divisible
Experiment with this code:

System.out.println( (10%5)  ); // will return 0
System.out.println( (10%4)  ); // will return 2

10 = 4 * 2 + 2
The green 2 is what the '%' returns. So if it is 0 it means that it is divisible