Converting long integer Into Array

[dieom]

What I am trying to accomplish here is to split a long integer apart so I can look at its first, last, and center digits. What I am currently using is this:

int main() {
  long i, t[1024];
  
  i = 100;

  while (i < 150) {
    t = i; // My attempt at converting the long into an array.
    printf("%ld\n", t[2]);
    i += 1;
  }

Any help would be appreciated!

[twomers]

Well. If it's the digits you're interested in you need only do:

lint main( int argc, char *argv[] ) {
  long num = 123;
  int dig1 = num % 10;
  int dig2 = (num/10) % 10;
  int dig3 = (num/100) % 10;
  printf( "%ld = %d %d %d\n", num, dig3, dig2, dig1 );

  return 0;
}

You can ceil the log of the long number to get the number of digits it has.

[Ancient Dragon]

you can not convert an integer to character array like you tried to do. Use sprintf() instead sprintf(t, "%ld", i);