int k=i++ + i++ + ++i + i++;
int m=j++ + j++ + j++ - j++;
cout<<i;
cout<<m;
cout<<j;
cout<<k;
what is the precedence in linux compiler
muthu1802 -4 Newbie Poster
Ancient Dragon 5,243 Achieved Level 70 Team Colleague Featured Poster
The result of that program is compiler dependent whether on *nix or any other operating system.
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